Answer: Probability that the proportion of students who graduated is greater than 0.743 is P = 0.4755
Step-by-step explanation:
Given that,
Probability of freshmen entering public high schools in 2006 graduated with their class in 2010, p = 0.74
Random sample of freshman, n = 81
Utilizing central limit theorem,

So,

= P( Z > 0.0616)
= 0.4755 ⇒ probability that the proportion of students who graduated is greater than 0.743.
Answer:
Step-by-step explanation:
3 and 2/5
(aka A)
Answer:
x = 9
TH = 12
Step-by-step explanation:
since TM is half of HM, the equation is:
2(21 - x) = 3x - 3
42 - 2x = 3x - 3
45 = 5x
x = 9
TH = 21 - x
TH = 21 - 9
TH = 12
Answer:
<h3>25%</h3>
Step-by-step explanation:
Total number of student in the school = 152 students
Number of student that have more than one pet = 38
percentage of the students have more than one pet will be expressed as
% of student with more than 1 pet = number of student with more than one pet/total number of student * 100%
% of student with more than 1 pet = 38/152 * 100
% of student with more than 1 pet = 3800/152
% of student with more than 1 pet = 25%
Hence 25% of the students in the school have more than one pet.