Question

What is the solution of sqareroot 1-3x = X+3?

Answer 1

Answer:

x=-8 or x=-1 (first option)

Step-by-step explanation:

$\sqrt{1-3x}=x+3\\1-3x=(x+3)^{2}$

now expand the bracket on the right

$1-3x=x^{2} +6x+9\\simplify:\\1-9=x^2+6x+3x\\-8=x^2+9x$

now make it a quadratic equation:

$x^2+9x+8=0\\factorise:\\(x+1)(x+8)\\so:\\x+1=0 \\x=-1\\\\and \\x+8=0\\x=-8$