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3 years ago

Find the missing angle

Mathematics

2 answers:

Mamont248 [21]3 years ago

6 0

Answer:

110 Degrees

Step-by-step explanation:

Every interior triangle equalls 180 degress. So you subtract what you already have from 180.

30+40+x=180

70+x=180

180-70=110

BlackZzzverrR [31]3 years ago

5 0

A triangle is always equals to 180 so you have to do:
40+30=70
180-70=110
F=110°

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Please may someone help me with this question thank you

Maru [420]

Answer:

C. $\frac{12}{7}$

Step-by-step explanation:

To find the slope when you know two points, use this formula:

M = y₂ - y₁ ÷ x₂ - x₁

M = (4 - (-8)) ÷ (0 - (-7))

M = 12 ÷ 7

M = $\frac{12}{7}$

Hope that helps.

3 0

2 years ago

Find the length of the following two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 < t < 16

andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

$r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)} dt$

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

$r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)} dt$

Doing the operations inside of the brackets the derivatives are:

1 ) $(\frac{d((1/2)t^2)}{dt} )^2= t^2$

2) $\frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1$

Entering these values of the integral is

$r(t)= \int\limits^{16}_{0} \sqrt{t^2 +2t+1} dt$

It is possible to factorize the quadratic function and the integral can reduced as,

$r(t)= \int\limits^{16}_{0} (t+1) dt= \frac{t^2}{2} + t$

Thus, evaluate from 0 to 16

$\frac{16^2}{2} + 16$

The value is $r= 144 units$

5 0

3 years ago

Si el lado de un cuadrado mide 10cm cuanto mide él área del círculo que se encuentra adentro de ese cuadrado

Alex17521 [72]

Answer:

El área del círculo que se encuentra en el cuadrado es de 78.5cm²

Step-by-step explanation:

Para resolver este ejercicio tenemos que pensar que un cuadrado tiene sus 4 lados iguales, por lo que todos sus lados medirán 10cm.

Ahora nos fijamos que necesitamos saber para calcular el área de un circulo

a = área

r = radio

π = 3.14

a = π * r²

como podemos ver no sabemos el valor del radio

como el circulo toca con los 4 lados del cuadrado sabemos que su radio sera la distancia del centro del cuadrado a cualquiera de los lados.

Entonces tenemos que dividir un lado por 2

10cm/2 = 5cm

El radio del circulo sera 5cm

Ahora que tenemos todos los datos podemos calcular el valor del área

a = 3.14 * (5cm)²

a = 3.14 * 25cm²

a = 78.5cm²

El área del círculo que se encuentra en el cuadrado es de 78.5cm²

8 0

3 years ago

Fast answeer plssss thank you thank you

vova2212 [387]

Select all the options because a rectangle can be made of all dimensions.

3 0

3 years ago

Plz i need help and plz explain

Montano1993 [528]

$\frac{ {x}^{2} - 7x + 12}{ {x}^{2} - x - 12 } \\ = \frac{ {x}^{2} - 4x - 3x + 12 }{ {x}^{2} - 4x + 3x - 12 } \\ = \frac{x(x - 4) - 3(x - 4)}{x(x - 4) + 3(x - 4)} \\ = \frac{(x - 3)(x - 4)}{(x + 3)(x - 4)} \\ = \frac{x - 3}{x + 3}$

x² - x - 12 ≠ 0

x² - 4x + 3x - 12 ≠ 0

x (x - 4) + 3 (x - 4) ≠ 0

(x + 3)(x - 4) ≠ 0

x ≠ -3 or x ≠ 4

(B)

3 0

3 years ago