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kupik [55]
3 years ago
6

phosporus can be prepared from calcium phosphate by the following reaction: 2Ca3(PO4)2+6SiO2+10C → 6CaSiO3+P4+10CO Phosphorite i

s a mineral that contains Ca3(PO4)2 by mass? Assume an excess of the other reactants plus other non-phosphorus-containing compounds. What is the maximum amount of P4 that can be produced from 1.9kg of phosphorite sample is 75% Ca3(PO4)2 by mass? Assume an excess of the other reactants
Chemistry
1 answer:
morpeh [17]3 years ago
6 0

Answer:

285 g of P₄

Explanation:

Let's consider the following balanced equation.

2 Ca₃(PO₄)₂ + 6 SiO₂ + 10 C → 6 CaSiO₃ + P₄ + 10 CO

We know the following relations:

  • 100 g of phosphorite contain 75 g of Ca₃(PO₄)₂
  • 2 moles of Ca₃(PO₄)₂ produce 1 mole of P₄
  • The molar mass of Ca₃(PO₄)₂ is 310 g/mol
  • The molar mass of P₄ is 124 g/mol

Then, for 1.9 kg of phosphorite:

1900g(phosphorite).\frac{75gCa_{3}(PO_{4})_{2}}{100g(phosphorite)} .\frac{1molCa_{3}(PO_{4})_{2}}{310gCa_{3}(PO_{4})_{2}} .\frac{1molP_{4}}{2molCa_{3}(PO_{4})_{2}} .\frac{124gP_{4}}{1molP_{4}} =285gP_{4}

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These 2 reactants will react to create an amount of a certain product in this case they're asking us for the amount of H2 that will be produced. Therefore, we need to find the REACTANT it can be either AL OR HCL.

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It's simple, because if you find the one that produces the less amount of H2, you know immediately that's the maximum amount of that product that will be produced.

Let's say you have a sandwich that needs to be made with 2 slices of bread, 3 meats and 1 cheese.

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