N2 + 3 H2 >> 2 NH3
moles NH3 = 11.50 g /17.0307 g/mol=0.6753
the ratio between H2 and NH3 is 3 : 2
moles H2 needed = 0.6753 x 3/2 =1.013
mass H2 = 1.013 mol x 2.106 g/mol=2.042 g
Keq= (products)/ (reactants)
Keq= ( [NO]^2 x [Cl2]) / ( [NOCl]^2)
Keq= ( (0.02)^2 x (0.01) ) / (0.5)^2= 1.6 x 10-5
Answer:
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