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Murrr4er [49]
2 years ago
13

PLEASE HELP FAST! 20 POINTS!!!

Mathematics
2 answers:
Lady bird [3.3K]2 years ago
4 0
Answer is

27%


step by step:

3/11 as a decimal is 0.27272 so on so on so Yep 27%
Sedbober [7]2 years ago
3 0

Answer:

27%

Step-by-step explanation:

3/11 = 0.27272727

so about 27%

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A single die is rolled one time. Find the probability of rolling a number greater than 4 or less than 3.
Vika [28.1K]

<u>Answer: </u>

The probability of rolling a number greater than 4 or less than 3 is \frac{2}{3}

<u>Solution: </u>

In the given question there are two events as follows:

(a) Rolling a number greater than 4 i.e. A = {5,6}

(b) Rolling a number less than 3 i.e. B = {1,2}

Since a die has 6 numbers,

 P(A) = \frac{2}{6} where P(A) is the probability of occurrence of event A and P(B) = \frac{2}{6}

Since, Event A and Event B has nothing in common therefore they are mutually exclusive events.

P(A∪B) = P(A) + P(B)

=\frac{2}{6}+\frac{2}{6}

=\frac{4}{6}

=\frac{2}{3}

Therefore the probability of getting a number greater than 4 or less than 3 is \frac{2}{3}

7 0
2 years ago
Solve st + 3t = 6 for s
vaieri [72.5K]

st + 3t = 6 for s

Subtract 3t to both sides

st + 3t  - 3t = 6 - 3t

Simplify

st = 6 - 3t

Divide both sides by t

st/t = (6-3t)/3

simplify

s = 6/3 - 3t/3

s = 2 - t


6 0
3 years ago
Tom finished 1/3 of the 30 problems assigned in class. Steven did 3/10 of the problems. Juan finished 20% of the problems. Marcu
RoseWind [281]

Answer: Tom

Step-by-step explanation:

Tom did 1/3 of 30= 10 out of 30

Steven did 3/10 of 30= 9 out of 30

Juan did 20/100 of 30= 6 out of 30

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6 0
3 years ago
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Kamila [148]

Answer:

C. 4.3 cm

Step-by-step explanation:

Since it is a right triangle you can use a²+b²=c² to solve this. Then you subtract 2 from the AC to get AD.

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3 years ago
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ycow [4]

9514 1404 393

Answer:

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Step-by-step explanation:

One way to write parametric equations for line L is ...

  L = P + t·<em>v</em>

where P is the given point and <em>v</em> is the given direction vector. Using that form, we have ...

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