Answer:
1188.0 mL.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and P are constant, and have two different values of V and T:
<em>V₁T₂ = V₂T₁
</em>
V₁ = 900 mL, T₁ = 27.0°C + 273 = 300.0 K.
V₂ = ??? mL, T₂ = 123.0°C + 273 = 396.0 K.
<em>∴ V₂ = V₁T₂/T₁ </em>= (900 mL)(396 K)/(300.0 K) = <em>1188.0 mL.</em>
Answer: 72L of 30% and 128L of 80%
You can determine the weight of the acid by multiplying the concentration with the volume. Let say v1 is the volume of 30% solution needed and v2 is the volume of 80% solution.
The weight of acid from the used solution should be equal to the product. You can get this equation
final solution= solution1 + solution2
200l * 62%= v1 * 30% + v2*80%
124L= 0.3v1 + 0.8v2
124L- 0.3v1= 0.8v2
v2=155L- 0.375v1
The total volume of both should be 200l. If you use the previous equation, you can calculate:
v1+v2=200L
v1+ (155L- 0.375v1)= 200L
0.625v1= 200L - 155L
v1= 45/ 0.625= 72L
v1+v2=200L
v2= 200L- 72L= 128L
Answer:
3.785411784
Explanation:1 gallon (gal) = 3.785411784 kilogram (kg). Gallon (gal) is a unit of Volume used in Standard system. Kilogram (kg) is a unit of Weight used in Metric system. Please note this is volume to weight conversion, this conversion is valid only for pure water at temperature 4 °C.
US oz = 28.349523125 g
US fl oz = 29.5735295625 ml (milliliters) = 29.5735295625 g (grams) of pure water at temperature 4 °C.
US cup = 8 fl oz = 236.5882365 ml (milliliters) = 236.5882365 g (grams) of pure water at temperature 4 °C.
The US gallon is equal to 3.785411784 liters and defined as 231 cubic inches. Kilograms also can be marked as kilogrammes in UK.
Answer: m Most likely Group2 metals and Group 17 non-ktta
Explanation:
A little more information is needed to be certain, but the likely answer is that X belongs to Group 2 and Y belongs to Group 17. Group 2 metals (Be, Mg, Ca, Sr, Ba, etc.) are all divalent. They gave rive up 2 electrons each to return to a full shell. Group 17 elements (e,g, F, Cl, Br, I, etc.) all require 1 electron to reach a full valence shell. That would make the proportion 1X to 2Y, or XY2. It is possible that a metal outside of Group 2 would also have a valency of 2. Iron(II) forms FeCl2, for example.
