Answer:
16.53 pounds
Explanation:
this type of problem needs convertion method we need to convert from grams to pound.
In order to calculate the number of atoms, we must first know the number of moles present. And
moles = (mass present) / (molecular mass)
Therefore, the moles of Mg present are
170 / 24 = 7.08
The number of atoms in a mole of substance is given by Avagadro's Number which is 6.02 x 10^23
Since there are 7.08 moles, there are:
7.08 * 6.02*10^23
= 4.26 * 10^24 atoms
between two oppositely charged ions
Answer:
The yearly release of
into the atmosphere is
.
Explanation:
![CaCO_3(s)\rightarrow CaO(s) + CO_2(g)](https://tex.z-dn.net/?f=CaCO_3%28s%29%5Crightarrow%20CaO%28s%29%20%2B%20CO_2%28g%29)
Annual production of CaO = ![8.6\times 10^{10} kg=8.6\times 10^{13} g](https://tex.z-dn.net/?f=8.6%5Ctimes%2010%5E%7B10%7D%20kg%3D8.6%5Ctimes%2010%5E%7B13%7D%20g)
Moles of CaO :
![\frac{8.6\times 10^{13} g}{56 g/mol}=1.53\times 10^{12} moles](https://tex.z-dn.net/?f=%5Cfrac%7B8.6%5Ctimes%2010%5E%7B13%7D%20g%7D%7B56%20g%2Fmol%7D%3D1.53%5Ctimes%2010%5E%7B12%7D%20moles)
According to reaction, 1 mole of CaO is produced along with 1 mole of carbon-dioxide.
Then along with
of CaO moles of carbon-dioxide moles produced will be:
of carbon-dioxide
Mass of
moles of carbon-dioxide:
![1.53\times 10^{12}mol\times 44 g/mol=6.73\times 10^{13} g =6.73\times 10^{10} kg](https://tex.z-dn.net/?f=1.53%5Ctimes%2010%5E%7B12%7Dmol%5Ctimes%2044%20g%2Fmol%3D6.73%5Ctimes%2010%5E%7B13%7D%20g%20%3D6.73%5Ctimes%2010%5E%7B10%7D%20kg)
The yearly release of
into the atmosphere is
.