So we can start with the full of possibilities and eliminate them one by one.
The full set is {0,1,2,3,4,5,6,7,8,9}.
Now we know that any prime greater than 2 is odd as otherwise it would have 2 as a factor, so we can eliminate all of these digits that would be an even number, leaving:
{1,3,5,7,9}
We also know that any prime greater than 5 cannot be a multiple of 5 and that all numbers with 5 in the digits are a multiple of 5, so we can eliminate 5.
{1,3,7,9}
We know that 11,13,17 and 19 are all primes, so we cannot eliminate any more of these, leaving the set:
{1,3,7,9} as our answer.
<h3>
Answer: Choice H) 2</h3>
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Explanation:
Recall that the pythagorean trig identity is 
If we were to isolate sine, then,
We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.
Through similar calculations, 
Cosine is also positive in this quadrant.
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So,
Therefore,
is an identity as long as 0 < x < pi/2
Well, it depends how much is each candy bar?
What is h?
maybe 25%
i hope it helped you sorry if it didn't
