The titration would require the same amount of NaOH.
<h3>Number of moles and dilution</h3>
The number of moles of solute in a solution remains the same irrespective of the amount of water added to dilute the solution.
This is in accordance with the dilution law which says that the number of moles of a solution before dilution is the same as after dilution.
Thus, the amount of NaOH needed to neutralize the vinegar will remain the same for a complete reaction since the number of moles of solute in the vinegar has not changed.
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- 1-ethyl-3-propylcyclopentane
- 1,2-dimethylcyclopentene
- 1,3,5-Triethylbenzene
<h3>What is IUPAC rule?</h3>
The IUPAC nomenclature system is a set of logical rules devised and used by organic chemists to circumvent problems caused by arbitrary nomenclature.
The 1-ethyl-3-propylcyclopentane molecule contains a total of 30 bond(s) There are 10 non-H bond(s), 3 rotatable bond(s) and 1 five-membered ring(s).
The 1,2-dimethylcyclopentene molecule contains two methyl groups and one double bond in the ring.
The 1,3,5-Triethylbenzene molecule contains three ethyl groups and a benzene ring.
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Enzymes are extremely selective catalysts that help to speed up reactions. The molecules an enzyme works with are called substrates and they bind to the enzyme. This helps speed up reactions greatly once the substrates bind to the active site of the enzyme.
Answer: There are two elements actually and those elements are Carbon and Silicon
Explanation:Plz mark brainliest if im right
Answer:
45.2%
Explanation:
To calculate the percent of an element in a compound we divide the molar mass of the element by the compound and multiply that by 100
First lets find the molar mass of Fluoride
Looking at the periodic table Fluoride has a molecular mass of 18.998 g
Now we need to find the molecular mass of NaF
Looking at a periodic table, Sodium (Na) has a molecular mass of 22.990g and Fluoride has a molecular mass of 18.998 so NaF has a molecular mass of 22.990(1) + 18.998(1) = 41.988g
Now we divide the mass of fluoride by the mass of sodium fluoride and multiply that by 100 to find the percentage of fluoride that is present in NaF
Mass of Fluoride = 18.998g
Mass of Sodium Fluoride = 41.988g
Percentage of fluoride present in NaF = (18.998g / 41.988g) * 100 = 45.2%