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ser-zykov [4K]
3 years ago
7

Ammonium hydroxide ionizes as follows: NH4OH(s) NH4 +(aq) + OH-(aq). If an excess of ammonium salt, such as NH4Cl (which ionizes

to give NH4 +(aq) ions) is added to the equilibrium shown above, you could predict that the result will be to....
Chemistry
2 answers:
Mice21 [21]3 years ago
8 0

Answer:

Concentration of OH- ions will be lowered

Explanation:

NH4OH is a weak electrolyte whereas NH4Cl is a strong electrolyte. The ionization can be depicted as follows:

NH4OH ↔ NH4+ + OH-

NH4Cl → NH4+ + Cl-

Addition of NH4Cl to NH4OH introduces a common ion i.e. NH4+.

The presence of a common ion supplied by a strong electrolyte will suppress the ionization of the weak electrolyte, this is called common ion effect.

In this case, the ionization of NH4OH will be suppressed which will lower the concentration of OH- ions.

Flauer [41]3 years ago
7 0
<span>Decrease the concentration of OH-</span>
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Answer:

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Explanation:

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6 0
3 years ago
A 10.21 mol sample of argon gas is maintained in a 0.7564 L container at 296.9 K. What is the pressure in atm calculated using t
soldi70 [24.7K]

Answer:

The pressure in atm calculated using the van der Waals' equation, is 337.2atm

Explanation:

This is the Van der Waals equation for real gases:

(P + a/v² ) ( v-b) = R .T

where P is pressure

v is Volume/mol

R is the gas constant and T, T° in K

a y b are constant for each gas, so those values are data, from the statement.

[P + 1.345 L²atm/mol² / (0.7564L/10.21mol)² ] (0.7564L/10.21mol - 3.219×10-2 L/mol ) = 0.082 L.atm/mol.K  .  296.9K

[P + 1.345 L²atm/mol² / 5.48X10⁻³ L²/mol²] (0.074 L/mol - 3.219×10-2 L/mol ) = 0.082 L.atm/mol.K  .  296.9K

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2 years ago
What is the concentration of FeCl3 in a solution prepared by dissolving 10.0 g of FeCl3 in enough water to make 275 mL of soluti
puteri [66]

Answer: The concentartion of solution will be 0.224 M

Explanation:

Molarity : It is defined as the number of moles of solute present per liter of the solution.

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{V_s} = volume of solution in ml = 275 ml

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Therefore, the concentration of solution will be 0.224 M

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