Question

At elevated temperatures, methylisonitrile (CH3NC) isomerizes to acetonitrile (CH3CN): CH3NC (g) → CH3CN (g) At the start of the experiment, there are 0.200 mol of reactant (CH3NC) and 0 mol of product (CH3CN) in the reaction vessel. After 25 min of reaction, 0.108 mol of reactant (CH3NC) remain. The average rate of decomposition of methyl isonitrile, CH3NC, in this 25 min period is ________ mol/min.

Answer 1

Answer:

Average rate of decomposition = 3.68 x 10⁻³ mol/min

Explanation:

CH₃NC (g) → CH₃CN (g)

Average rate of decomposition = [CH₃NC]/Δt

[CH₃NC] = initial [CH₃NC] - final [CH₃NC]

[CH₃NC] = 0.200 mol - 0.108 mol

[CH₃NC] = 0.092 mol

Average rate of decomposition = 0.092 mol / 25 min

Average rate of decomposition = 3.68 x 10⁻³ mol/min