The equation of an ellipse for the graph shown is 
<h3>How to determine the equation?</h3>
Since the given coordinates of the vertices and foci have the form (-5, 0) and (5, 0) and (-2, 0) and (2, 0) respectively, this ultimately implies that the major axis of this ellipse is the x-axis.
Thus, the standard form of the equation of this ellipse is given by:
Next, we would solve for b² by using this equation:
b² = a² - c²
b² = 5² - 2²
b² = 25 - 4
b² = 21.
Substituting the parameters into the standard equation of an ellipse, we have;
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Answer:
b
Step-by-step explanation:
r=d/2=11.4/2=5.7
slant surface area=2πr*h=11.4×3.14×4.4=157.5024 cm^2
area of base and top=2(πr²)=2×3.14×(5.7)²=204.0372 cm²
total surface area=157.5024+204.0372=361.5396=361.5 sq. cm
Answer:
-5/6
Step-by-step explanation:
This is because we can substitute p for 2/3.
(3/4 x 2/3) - (2/1 x 2/3)
This shall equal:
6/12 - 4/3
In order to subtract, we need the same denominator meaning we need that three on 4/3 to be 12. So multiply 4/3 and 4/4
Equation shall be like this:
6/12 - 16/12
Now subtract keep the denominator the same!
-10/12
Simply/reduce (divide by 2/2)
-5/6!!
Y = mx + c
m = 2
y = 2x + c
At (5, 0)
0 = 2(5) + c
c = -10
y = 2x - 10
