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3 years ago

A food processor draws 8.47 A of current when connected to a potential difference of 110 V.

Physics

1 answer:

Andreyy893 years ago

3 0

Answer:

27.95[kW*min]

Explanation:

We must remember that the power can be determined by the product of the current by the voltage.

$P=V*I$

where:

P = power [W]

V = voltage [volt]

I = amperage [Amp]

Now replacing:

$P=110*8.47\\P=931.7[W]$

Now the energy consumed can be obtained mediate the multiplication of the power by the amount of time in operation, we must obtain an amount in Kw per hour [kW-min]

$Energy = 931.7[kW]*30[days]*10[\frac{min}{1day} ]=279510[W*min]or 27.95[kW*min]$

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Fission fusion worksheet answers

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3 years ago

2. A 2.5 meter-long wave travels at 1 m/s towards a fixed boundary. After 2 seconds, how does the wave appear?

Elan Coil [88]

Answer:

Since incident wave and its reflected part in opposite phase superimpose on each other

So correct answer will be

Option B

Explanation:

Here we know that the wave reflection is done by rigid boundary

So when wave is reflected by the boundary then its phase is reversed by 180 degree

so the reflected wave is in reverse phase from the boundary

so we can superimpose the reflected part with incident wave to dine the resultant wave

So the phenomenon is given as follow

6 0

3 years ago

A horizontal spring is attached to a wall at one end and a mass at the other. The mass rests on a frictionless surface. You pull

Kaylis [27]

Answer:

Δt'/ T% = 90.3%

Explanation:

Simple harmonic movement is described by the expression

x = A cos (wt)

we find the time for the two points of motion

x = - 0.3 A

-0.3 A = A cos (w t₁)

w t₁ = cos -1 (-0.3)

remember that angles are in radians

w t₁ = 1.875 rad

x = 0.3 A

0.3 A = A cos w t₂

w t₂ = cos -1 (0.3)

w t₂ = 1,266 rad

Now let's calculate the time of a complete period

x= -A

w t₃ = cos⁻¹ (-1)

w t₃ = π rad

this angle for the forward movement and the same time for the return movement in the oscillation to the same point, which is the definition of period

T = 2 t₃

T = 2π / w s

now we can calculate the fraction of time in the given time interval

Δt / T = (t₁ -t₂) / T

Δt / T = (1,875 - 1,266) / 2pi

Δt / T = 0.0969

This is the fraction for when the mass is from 0 to 0.3, for regions of oscillation of greater amplitude the fraction is

Δt'/ T = 1 - 0.0969

Δt '/ T = 0.903

Δt'/ T% = 90.3%

4 0

3 years ago

How much energy is needed to perform 300 J of work?

4vir4ik [10]

I think this is the answer hope it helps

3 0

3 years ago

Two objects with masses m and 3m are connected by a compressed spring so that the energy stored in the spring is 375 joules. If

cluponka [151]

Answer:

281.25 J

Explanation:

We are told that the two objects with masses m and 3m.

Also that energy stored in the spring is 375 joules.

Now, initially the centre of mass of the system took place at rest, it means v1 = v and v2 = v/3

Thus, from principle of conservation of energy, we have;

½mv² + ½(3m)(v/3)² = 375J

(m + 3m/9)½v² = 375

(4/3)m × ½v² = 375

Multiply both sides by ¾ to get;

½mv² = 375 × ¾

½mv² = 281.25 J

Therefore, energy of lighter body is 281.25 J

7 0

2 years ago