Why are electromagnets used in metal scrap yards<br> PLEASE HELP!!!!!!

Estimate the kinetic energy of the Mars with respect to the Sun as the sum of the terms, that due to its daily rotation about it

kotykmax [81]

Answer:

K = 2.07 10³⁹ J

Explanation:

This problem must be solved using rotational kinematics.

Kinetic energy has the form

K = ½ m v²

Linear velocity is related to angular velocity.

v = w r

replace

K = ½ m R² w²

With this equation we can find the total kinetic energy of Mars, formed by the rotation energy plus the translational energy

K = Kr + Kt

Where Kr is the energy by the rotation on its axis and Kt is the energy by the rotation around the sun.

Let's reduce to SI units

Rotation T₁ = 24.7 h (3600 s / 1 h) = 88920 s

R₁ = 3.4 10⁶ m

translation T₂ = 686 day (24 h / 1 day) (3600 s / 1 h) = 5.927 10⁷ s

R₂ = 2.3 10⁸ km (1000 m / 1 km) = 2.3 10¹¹ m

The angular velocity is the angle rotated (radians) between the time taken, in this case as the order gives us the angle is 2pi rad (360º). Remember that the equations work only in radians

Rotation

wr = 2π / T₁

wr = 2 π / 88920

wr = 7.066 10⁻⁵ rad / s

Translation

wt = 2 π / T₂

wt = 2 π / 5,927 10⁷

wt = 1.06 10⁻⁷-7 rad/s

Let's explicitly write the equation of kinetic energy and calculate

K = ½ m R₁² wr² + ½ m R₂² wt²2

K = ½ m (R₁² wr² + R₂² wt²)

K = ½ 6.4 10²³ [(3.4 10⁶)² 7.066² + (2.3 10¹¹)² (1.06 10⁻⁷)²]

K = 3.2 10²³ [61.49 10¹² + 6.414 10¹⁵]

K = 3.2 10²³ [61.49 10¹² + 6414 10¹²]

K = 3.2 10²³ (6475 10¹²)

K = 2.07 10³⁹ J

5 0

3 years ago

A batter hits a 0.140-kg baseball that was approaching him at 50.0 m/s and, as a result, the ball leaves the bat at 35.0 m/s in

KonstantinChe [14]

Answer:

Impulse, J = 2.1 kg-m/s

Explanation:

Given that,

Mass of baseball, m = 0.14 kg

It was approaching him at 50.0 m/s and, as a result, the ball leaves the bat at 35.0 m/s in the direction of the pitcher. We need to find the magnitude of Impulse delivered to the baseball.

The change in momentum is equal to the Impulse imparted to the ball i.e.

$J=m(v-u)$

$J=0.14(-35-50)$

J = -2.1 kg-m/s

So, the Impulse delivered to the baseball is 2.1 kg-m/s

7 0

4 years ago

Consider a situation where you are playing air hockey with a friend. The table shoots small streams of air upward to keep the pu

artcher [175]

When we hit the puck from tap the puck will move forward.

This is due to the impulse provided by us at the time of hit. Due to this impulse the puck will move forward and start moving in some direction.

As soon as puck move forward the force on it is zero as the weight of the puck is counterbalanced by the air stream force and there is no other force on it so puck will continue its motion till it will hit at some other point.

So here the motion of the puck will be uniform motion till it will collide with some other points.

So here the correct option will be given as

<em>moves with a constant speed until hitting the other end.</em>

5 0

4 years ago

How do u find a worm hole

Zinaida [17]

No one knows if they even exist so you can't really find one

3 0

4 years ago

Read 2 more answers

The burner on an electric stove has a power output of 2.0 kW. A 650 g stainless steel tea kettle is filled with 20∘C water and p