Answer:
stronger forces between particles means the substance boils at a higher temperature.
Explanation:
A.pex
Subcutaneous fat is the fat that lies under the skin and isn’t necessarily harmful to your health and visceral fat is the harmful unseen fat surrounding the organs.
The time elapsed when the vehicles are closest to each other is 20 min.
The given parameters:
- Speed of the truck, u = 80 km/h
- Distance, d = 32 km
- Speed of the car, v = 50 km/h
<h3>Principles of relative speed</h3>
The time elapsed when the cars are close to each other is calculated by applying the principles of relative speed.


Thus, the time elapsed when the vehicles are closest to each other is 20 min.
Learn more about relative velocity here: brainly.com/question/24430414
A) GPS monitoring of plate speeds and movements.
Explanation:
The most recent evidence supporting the theory of plate tectonics would be GPS monitoring of plate speeds and movements.
A GPS is a Global Positioning System made up of series of components.
- Plate tectonics theory is the movement of the earth's lithosphere relative to one another.
- The recent advances uses a GPS system to monitor real-time movement of the plates.
- The GPS system is made up of a system of satellite in space that communicates real-times locations to sensors on the earth surface.
- From the sensors, observatory stations can know and duly observe how plates are moving.
learn more:
Lithosphere brainly.com/question/9582362
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Answer:
Answer:
Explanation:
Given that
K=8.98755×10^9Nm²/C²
Q=0.00011C
Radius of the sphere = 5.2m
g=9.8m/s²
1. The electric field inside a conductor is zero
εΦ=qenc
εEA=qenc
net charge qenc is the algebraic sum of all the enclosed positive and negative charges, and it can be positive, negative, or zero
This surface encloses no charge, and thus qenc=0. Gauss’ law.
Since it is inside the conductor
E=0N/C
2. Since the entire charge us inside the surface, then the electric field at a distance r (5.2m) away form the surface is given as
F=kq1/r²
F=kQ/r²
F=8.98755E9×0.00011/5.2²
F=36561.78N/C
The electric field at the surface of the conductor is 36561N/C
Since the charge is positive the it is outward field
3. Given that a test charge is at 12.6m away,
Then Electric field is given as,
E=kQ/r²
E=8.98755E9 ×0.00011/12.6²
E=6227.34N/C