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Gala2k [10]
3 years ago
5

In fighting forest fires, airplanes work in support of ground crews by dropping water on the fires. For practice, a pilot drops

a canister of red dye, hoping to hit a target on the ground below. If the plane is flying in a horizontal path 90.0 m above the ground and has a speed of 64.0 m/s (143 mi/h), at what horizontal distance from the target should the pilot release the canister? Ignore air resistance.
Physics
1 answer:
Brut [27]3 years ago
4 0

Answer:

s=274.2857\ m is the distance from the target before which the pilot must release the canister.

Explanation:

Given:

  • height of the plane, h=90\ m
  • horizontal speed of plane, v_x=64\ m.s^{-1}

<u>Time taken by the canister to hit the ground:</u>

using equation of motion

h=u_y.t+\frac{1}{2} g.t^2

where:

u_y= initial vertical velocity of the canister = 0 (since the the object is dropped from a horizontally moving plane)

t= time taken to hit the ground

90=0+0.5\times 9.8\times t^2

t=4.2857\ s

<u>Now the horizontal distance travelled by the canister after dropping:</u>

s=v_x\times t

s=64\times 4.2857

s=274.2857\ m is the distance from the target before which the pilot must release the canister.

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In terms of their location, what is the difference between subcutaneous fat and visceral fat
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A truck is traveling east at 80 km/h. At an intersection 32 km ahead, a car is traveling north at 50 km/h. How long after this m
nirvana33 [79]

The time elapsed when the vehicles are closest to each other is 20 min.

The given parameters:

  • Speed of the truck, u = 80 km/h
  • Distance, d = 32 km
  • Speed of the car, v = 50 km/h

<h3>Principles of relative speed</h3>

The time elapsed when the cars are close to each other is calculated by applying the principles of relative speed.

(V_r) t = d\\\\V_r^2 = 50^2 + 80^2\\\\V_r =\sqrt{50^2 + 80^2} \\\\V_r = 94.34 \ km/h

94.34 t = 32\\\\t = \frac{32}{94.34} \\\\t = 0.34 \ hr\\\\t \approx 20 \min

Thus, the time elapsed when the vehicles are closest to each other is 20 min.

Learn more about relative velocity here: brainly.com/question/24430414

3 0
2 years ago
The most recent evidence supporting the theory of plate tectonics would include A) GPS monitoring of plate speeds and movements.
Whitepunk [10]

A) GPS monitoring of plate speeds and movements.

Explanation:

The most recent evidence supporting the theory of plate tectonics would be GPS monitoring of plate speeds and movements.

A GPS is a Global Positioning System made up of series of components.

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  • The recent advances uses a GPS system to monitor real-time movement of the plates.
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3 years ago
The dome of a Van de Graaff generator receives a charge of 0.00011 C. The radius of the dome is 5.2 m. Find the strength of the
wel

Answer:

Answer:

Explanation:

Given that

K=8.98755×10^9Nm²/C²

Q=0.00011C

Radius of the sphere = 5.2m

g=9.8m/s²

1. The electric field inside a conductor is zero

εΦ=qenc

εEA=qenc

net charge qenc is the algebraic sum of all the enclosed positive and negative charges, and it can be positive, negative, or zero

This surface encloses no charge, and thus qenc=0. Gauss’ law.

Since it is inside the conductor

E=0N/C

2. Since the entire charge us inside the surface, then the electric field at a distance r (5.2m) away form the surface is given as

F=kq1/r²

F=kQ/r²

F=8.98755E9×0.00011/5.2²

F=36561.78N/C

The electric field at the surface of the conductor is 36561N/C

Since the charge is positive the it is outward field

3. Given that a test charge is at 12.6m away,

Then Electric field is given as,

E=kQ/r²

E=8.98755E9 ×0.00011/12.6²

E=6227.34N/C

5 0
3 years ago
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