Answer : The pH of buffer is 9.06.
Explanation : Given,
Concentration of HBrO = 0.34 M
Concentration of KBrO = 0.89 M
Now we have to calculate the pH of buffer.
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[KBrO]}{[HBrO]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BKBrO%5D%7D%7B%5BHBrO%5D%7D)
Now put all the given values in this expression, we get:
Therefore, the pH of buffer is 9.06.
Answer:
True
Explanation:
In a given molecule protons in the same chemical environment absorb at the same applied field strength; whereas protons with different chemical environments absorb at different applied field strengths.
A set of protons in the same chemical environment are said to be equivalent. Hence, the number of signals in the NMR spectrum tell us the number of sets of equivalent protons present in the molecule.
Splitting of a signal in a proton NMR spectrum tells us the number of chemically non-equivalent hydrogens in the immediate vicinity of the hydrogen giving the signal.
Answer:
39.099 amu
Explanation:
saw this on quizlet no cap sorry im 3 weeks late
