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777dan777 [17]
3 years ago
7

Which is the equivalent of 12.42 written in DMS form?

Mathematics
2 answers:
scZoUnD [109]3 years ago
7 0

Answer:

DMS form =  12°25'12''.

Step-by-step explanation:

Given :  12.42.

To find : written in DMS form.

Solution : We have given that  12.42.

Multiply 42 by 60 to convert it in to minute

We can write it as  12 + .42(60).

12°25.2'

Rewrite 12°25+.2'

2' = 2 ( 60) to convert minute in to second.

12°25+.2(60)

12°25'12''

Therefore, DMS form =  12°25'12''.

nika2105 [10]3 years ago
3 0
12.42

12°+.42(60)

12°25.2'

12°25'+.2(60)

12°25'12"
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Omar is 14 years old and 6 feet tall. If he has grown .5 feet each year for the past 3 years, how tall was he when he was 12 yea
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He was 4 foot. With this I just took .5 and multiplyed it by 4, then subtracted it from 6. Hope this can help! Feel free to message me if you have anymore questions!
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3 years ago
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Mario buys tickets for either 47 or 57 dollars. He purchases 14 tickets and spends 738 dollars. How many tickets did he purchase
Ivanshal [37]

Answer:

6 tickets were purchased at $47

8 tickets were purchased at $57

Step-by-step explanation:

Let the tickets purchased at $47 be x

Let the tickets purchased at $57 be y

We can form an equation from the question given which will be:

x + y = 14 ....... i

47x + 57y = 738 ........ ii

From equation i

x = 14 - y ........ iii

Substitute iii into ii

47x + 57y = 738

47(14-y) + 57y = 738

658 - 47y + 57y = 738

Collect like terms

-47y + 57y = 738 - 658

10y = 80

y = 80/10

y = 8

8 tickets were purchased at $57

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x + y = 14

x + 8 = 14

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6 tickets were purchased at $47

7 0
3 years ago
Solve 8(m - 5 ) = 48
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Answer

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2)x + 7 = 13 \\ x = 13 - 7 \\ x = 6

3)3h - 5 = 12 \\ 3h = 12 + 5 \\ 3h = 17 \\  \frac{3h}{3}  =  \frac{17}{3}  \\ h = 5 \frac{2}{3}

Hope this helps you.

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4 0
3 years ago
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{4x-2y+5z=6 <br> {3x+3y+8z=4 <br> {x-5y-3z=5
lesya692 [45]

There are three possible outcomes that you may encounter when working with these system of equations:


  •    one solution
  •    no solution
  •    infinite solutions

We are going to try and find values of x, y, and z that will satisfy all three equations at the same time. The following are the equations:

  1. 4x-2y+5z = 6
  2. 3x+3y+8z = 4
  3. x-5y-3z = 5

We are going to use elimination(or addition) method

Step 1: Choose to eliminate any one of the variables from any pair of equations.

In this case it looks like if we multiply the third equation by 4 and  subtracting it from equation 1, it will be fairly simple to eliminate the x term from the first and third equation.

So multiplying Left Hand Side(L.H.S) and Right Hand Side(R.H.S) of 3rd equation with 4 gives us a new equation 4.:

4. 4x-20y-12z = 20      

Subtracting eq. 4 from Eq. 1:

(L.HS) : 4x-2y+5z-(4x-20y-12z) = 18y+17z

(R.H.S) : 20 - 6 = 14

5. 18y+17z=14

Step 2:  Eliminate the SAME variable chosen in step 2 from any other pair of equations, creating a system of two equations and 2 unknowns.

Similarly if we multiply 3rd equation with 3 and then subtract it from eq. 2 we get:

(L.HS) : 3x+3y+8z-(3x-15y-9z) = 18y+17z

(R.H.S) : 4 - 15 = -11

6. 18y+17z = -11

Step 3:  Solve the remaining system of equations 6 and 5 found in step 2 and 1.

Now if we try to solve equations 5 and 6 for the variables y and z. Subtracting eq 6 from eq. 5 we get:

(L.HS) : 18y+17z-(18y+17z) = 0

(R.HS) : 14-(-11) = 25

0 = 25

which is false, hence no solution exists



3 0
3 years ago
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