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Inessa05 [86]
3 years ago
13

Simplify.

Mathematics
2 answers:
hjlf3 years ago
6 0

Answer:

<h3>33x+3x(2)-1</h3>

Step-by-step explanation:

<h2><em>Hope This Helps</em></h2>

hammer [34]3 years ago
5 0

Answer:

(x+3)(x−1)x

Step-by-step explanation:

It is this option

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The Pyramid of Khafre measured 143.5
nadezda [96]

Answer:

what are the answers that are given

Step-by-step explanation:

6 0
4 years ago
!!please, please help me!!
grigory [225]

Answer:

Length: 12

Width: 2\sqrt{10\\}

Area: 24\sqrt{10\\}

Step-by-step explanation:

We first find the points of C and D to find the length.

C: (-4,-5)

D: (2,-3)

The distance is 2\sqrt{10\\.

Now for the height.

A: (2,9)

D: (2,-3)

The distance is 12.

Area: 2\sqrt{10\\×12 = 24\sqrt{10\\}

6 0
3 years ago
Which decimal is equivalent to 2/9?
Andrej [43]

Answer:

0.222222222

Step-by-step explanation:

in fractions, the / represents division.

so, we do:

2 ÷ 9 = 0.222222222

Hope this helps.

5 0
1 year ago
HELP PLEASE!!!!!!
Westkost [7]
False true true false true false
8 0
3 years ago
Read 2 more answers
As a nasal decongestant, doctors sometimes prescribe saline solutions with a concentration between 6% and
marishachu [46]

Answer:

18mL of  the 20% solution must be mixed with 10 mL of the 6% solution to

obtain the desired 15% solution

Step-by-step explanation:

Ignore all of the useless information til the last sentence: How many milliliters of the 20% solution must be mixed with 10 mL of the 6% solution to  obtain the desired 15% solution?

Our goal is to find out how many mL of 20% solution is needed to mix with 10mL of 6% solution to achive a 15% solution.

An easy and simple way to do it is to create a system of equation:

We add in x mL of 15% solution(Which has x mL of water and 20%*x mL of salt)

The equation: 15%=(20%x+0.6)/(x+10)

After solving it we get x=18

Therefore:

18mL of  the 20% solution must be mixed with 10 mL of the 6% solution to

obtain the desired 15% solution

Hope this helps, have a good day!

Ps. If you have any questions, feel free to ask them in the comment section below-I'll be more than happy to answer.

4 0
3 years ago
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