Intermediate Value Theorem: Suppose that f(x) is an arbitrary, continuous function on an interval [a,b] . If there exists a value L between f(a) and f(b) , then there exists a corresponding value c∈(a,b) , such that f(c)=L
f(x)=x3+4x−1
f(0)=−1f(1)=4
Since the function changes sign in the interval (0,1) , hence there exists a c∈(0,1) such that f(c)=0
You can determine if the answer is positive or negative because the even numbers are positive and the odd numbers are negative
Answer:
-3
Step-by-step explanation:
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