Answer:
a) ρ = 3.735 Kg/m³
b) γ = 36.603 N/m³
c) Vw = 2.68 E-4 g/m³
Explanation:
- PV = RTn .....ideal gas law
a) ρ = m/V
∴ Mw air = 28.966 g/mol......from literature
⇒ P = RTn / V
∴ n = m / Mw
⇒ P = mRT / Mw.V = m/V * R.T/Mw
∴ P = 50 psi = 344738 Pa
∴ R = 8.3144 Pa.m³/mol.K
∴ T = 120°F = 48.889 °C = 321.889 K
⇒ ρ = (( 344738 Pa ) * ( 28.996 g/mol )) / (( 8.3144 Pa.m³/mol.K) * ( 321.889K ))
⇒ ρ = 3734.996 g/m³ * ( Kg / 1000g ) = 3.735 Kg/m³
specific weight:
- γ = w / V = m.g / V = ρ *g
∴ ρ = 3.735 Kg/m³
∴ g = 9.8 m/s²
⇒ γ = 36.603 N/m³
c) specific volume
⇒ Vw = (( 8.3144 Pa.m³/ mol.K ) * ( 321.889 K )) / ( 344738 Pa )* ( 28.966 g/mol)
⇒ Vw = 2.68 E-4 g/m³
<span>You need information that you haven't provided in the question. Perhaps your text has a table of ΔGof for these compounds. In that case,
ΔGorxn = Sum of ΔGof products - ΔGof reactants
Just plug in the values that you find and calculate the free energy change of the reaction</span>
Wax is susceptible to heat. Wax is responds to heat addition. The forces in the wax when heat is added are being broken off and are much lesser as its original state. Hope this answers the question. Have a nice day.<span />
Answer;
-3.0 mole at 25 °C
Explanation;
-Temperature is a measure of average kinetic energy. If the samples are at the same temperature, they have the same average kinetic energy.
-Kinetic energy is related to the temperature (temperature is a measure of kinetic energy). Therefore; the higher the temperature the more kinetic energy. Because water is at 25 Celsius then the LiCl would have to be at 25 Celsius to have the same kinetic energy.
Answer:
Mass of CaBr₂ = 179.9 g
Explanation:
Given data:
Volume of CaBr₂ solution = 450.0 mL (450/1000 = 0.45 L)
Molarity of solution = 2.00 M
Mass of CaBr₂ = ?
Solution:
Formula:
Molarity = number of moles / volume of solution in L
Now we will put the values.
2.00 M = number of moles / 0.45 L
Number of moles = 2 M × 0.45 L
Number of moles = 0.9 mol ( M = mol/L)
Mass of CaBr₂:
Mass of CaBr₂ = number of moles × molar mass
Mass of CaBr₂ = 0.9 mol × 199.89 g/mol
Mass of CaBr₂ = 179.9 g