MgO
MgI2
PbO2
PbI4
These are the possible compounds
The density of the sample is 0.96 g/mL.
Density is found by dividing the mass of an object by its volume.
D=m÷v
D=35.4 g÷36.82 mL
D=0.96 g/mL
Answer:
A certain portion of the land will be set aside as wildlife habitat
You should classify it as co2 solid as CO2(s) and that small left comes to the bottom right hand side and dry ice is a form of liquid carbon dioxide so u should write it as CO2(l) and that L comes to the bottom right hand sise
The answer is mass.
Mass is the amount of matter in an object. So no matter where the object is, it mass will stay the same unless particles are increased.
