All categories

3 years ago

The force resulting from oppositely charged poles is ...

Chemistry

1 answer:

lys-0071 [83]3 years ago

3 0

Energy is coming

Lmk if this helps

You might be interested in

What is the fee for a law and rules book

aivan3 [116]

$14.00

fee for a Law and rule book

7 0

3 years ago

Draw the structure(s) of all of the possible monochloro derivatives of 2,4-dimethylpentane, c7h15cl.

pishuonlain [190]

The monochloroderivatives will be obtained by substituting chemically non equivalent hydrogen with chlorine atom, one by one

So the possible monochloro derivatives of 2,4-dimethylpentane (figure 1) are shown in figure (2)

7 0

3 years ago

Suppose you are trying to find the volume of a box based on the following measurements for the length, width, and height of the

Dahasolnce [82]

Answer:

87.78 in cubed

Explanation:

excuse me if I am wrong i tried my best

don't know if its right

5 0

3 years ago

Science is based primarily on peoples opinions and views of the subject matter.

kvv77 [185]

Answer:

False

Explanation:

Science is not based on primarily on peoples opinions and views of the subject matter whereas science is based on empirical observations and research for its validity.

<u>Science aims to find answers to human questions related to the natural world through their research observation and experiments. Scientists and researchers provide valid proof of human questions so that people can trust them.</u>

Science can change people's opinions regarding the natural world with valid proof and observational theories but science is not based on people's opinion.

Hence, the given statement is "false".

7 0

3 years ago

Flourine is found to undergo 10% radioactivity decay in 366 minutes determine its halflife

yuradex [85]

Answer:

$\boxed{\text{2408 min}}$

Explanation:

The integrated rate law for radioactive decay is

$\ln\dfrac{N_{0}}{N_{t}} = kt$

1. Calculate the decay constant

$\begin{array}{rcl}\ln \dfrac{100}{90} & = & k \times 366\\\\1.054 & = & 366k\\\\k & = & \dfrac{1.054 }{366}\\\\k & = & 2.879 \times 10^{-4} \text{ min}^{-1}\\\end{array}\\\\$

2. Calculate the half-life

$t_{\frac{1}{2}} = \dfrac{\ln2}{k}\\\\t_{\frac{1}{2}} = \dfrac{\ln2}{2.879 \times 10^{-4} \text{ min}^{-1}} = \text{2408 min}\\\\\text{The half-life for decay is } \boxed{\textbf{2408 min}}$

8 0

3 years ago