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gogolik [260]
3 years ago
10

Each compound listed is soluble in water. For each compound, do you expect the resulting aqueous solution to conduct electrical

current? Why?
a) CsCl
b) CH3OH
c) Ca(NO2)2
d) C6H12O6
Chemistry
1 answer:
Strike441 [17]3 years ago
5 0

Answer:

See below in bold.

Explanation:

a) Yes  because it is an ionic compound. Forms ions in water solution.

b) This is an alcohol with covalent bonds it does not ionise in water - no.

c) Yes this forms ions in water solution.

d) This is a sugar and does not ionise so No.

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Which particle often described as having very little or no mass since the mass number does not change when you add more and more
astra-53 [7]

Answer:

I wrote this answer to get points lol

Explanation:

7 0
3 years ago
Families 1-2 and 13-18 are called the...
Zolol [24]

Answer:

C. representative elements.

Explanation:

Families 1 - 2 and 13 - 18 are called representative elements or often times, main group elements.

  • Elements on the periodic table belongs to four blocks which are s, p, d and f blocks.
  • Those in the s and p-blocks are the main group elements also called representative elements.
  • Their outer-shell are not completely filled with electrons but their inner shell is completely filled.
5 0
3 years ago
How do hydroxyl ions and hydronium ions affect pH?
Nookie1986 [14]
Hydroxyl ions are OH⁻ while hydronium ions are H₃O⁺ which is essentially H⁺ ions. The formula for pH is: pH = -log[H⁺]. So, the greater the concentration of H⁺ is, the lower the pH which indicates acidity. On the other hand, the greater the concentration of OH⁻, the greater the pH which indicates basicity. This is also a consequence of the equation: pH + pOH = 14.
4 0
4 years ago
A metal, M, forms an oxide having the formula MO2 containing 59.93% metal by mass. Determine the atomic weight in g/mole of the
Damm [24]

Answer:

See solution.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to set up the formula for the calculation of the by-mass percentage of the metal:

\%  M=\frac{m_M}{m_M+2*m_O}*100 \%\\\\59.93\%  =\frac{m_M}{m_M+32.00}*100 \%

Thus, we solve for the molar mass of the metal to obtain:

59.93\% (m_M+32.00) =m_M*100 \%\\\\m_M*59.93\% +1917.76\% =m_M*100 \%\\\\m_M=47.86g/mol

For the subsequent problems, we proceed as follows:

a.

4.00gO_2*\frac{1molO_2}{32.00gO_2}=0.125molO_2

b.

0.400molH_2S*\frac{2molH}{1molH_2S}*\frac{6.022x10^{23}atomsH}{1molH}=4.82x10^{23}atomsH

c.

0.235gNH_3*\frac{1molNH_3}{17.03gNH_3} *\frac{3molH}{1molNH_3}*\frac{6.022x10^{23}atomsH}{1molH}=2.49x10^{22}atomsH

Regards!

7 0
3 years ago
If a 58 g sample of metal at 100 c is placed into calorimeter containing 60g of water at 18 c , the temperature of the water inc
tatiyna

Answer:

The water will absorb 1004.16 Joule of heat

Explanation:

Step 1: Data given

Mass of the metal = 58.00 grams

Temperature of the metal = 100.00 °C

Mass of water = 60.00 grams

Temperature of water = 18.00 °C

Final temperature = 22.00 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate the amount of heat absorbed by the water in joules

Q = mass *specific heat *ΔT

 ⇒ with Q = the heat absorbed by water

⇒ with mass of water = 60.00 grams

⇒ with specific heat of water = 4.184 J/g°C

⇒ with ΔT = The change in temperature of water = T2 - T1 = 22 - 18 = 4.0 °C

Q = 60.00 * 4.184 J/g°C * 4.0 °C

Q = 1004.16 J

The water will absorb 1004.16 Joule of heat

6 0
3 years ago
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