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Answer : The final pressure in the system is 4.22 atm.
Explanation :
First we have to calculate the moles of methane.
where,
P = pressure of gas = 9.61 atm
V = volume of gas = 3.06 L
T = temperature of gas = T
= number of moles of methane gas = ?
R = gas constant
Now put all the given values in the ideal gas equation, we get:
Now we have to calculate the moles of oxygen gas.
where,
P = pressure of gas = 1.75 atm
V = volume of gas = 6.65 L
T = temperature of gas = T
= number of moles of oxygen gas = ?
R = gas constant
Now put all the given values in the ideal gas equation, we get:
Now we have to determine the final pressure in the system after mixing the gases.
where,
= final pressure of gas = ?
= final volume of gas = (3.06 + 6.65)L = 9.71 L
T = temperature of gas = T
R = gas constant
Now put all the given values in the ideal gas equation, we get:
Therefore, the final pressure in the system is 4.22 atm.
2.258302785 x atoms of titanium are present in a sample containing 0.375 moles of Ti.
A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
To find the number atoms we need to multiply by 6.02214076 × 10^{23}.
0.375 moles x 6.02214076 ×
2.258302785 x
Hence, 2.258302785 x atoms of titanium are present in a sample containing 0.375 moles of Ti.
Learn more about moles here:
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