Answer:
2Cu2^+ + 2I^- ----> 2Cu^+ + I2
Explanation:
The reaction performed in the experiment is;
2 Cu(NO3)2 + 4 KI → 2 CuI (s) + 4 KNO3 + I2
The iodide ions reduces Cu^2+ to Cu^+ which is insoluble in water hence the precipitate. This is so because iodine is a good oxidizing agent seeing that it requires one electron to fill its outermost shell. Potassium on the other hand is a good reducing agent since it easily looses its one electron.
The oxidation - reduction equation is as follows;
2Cu2^+ + 2e ----> 2Cu^+ reduction half equation
2I^- ----> I2 + 2e. Oxidation half equation
Balanced redox reaction equation;
2Cu2^+ + 2I^- ----> 2Cu^+ + I2
If a metal is less reactive than carbon, it can be extracted from its oxide by heating with carbon. The carbon displaces the metal from the compound, and removes the oxygen from the oxide. This leaves the metal.
The variables in the ideal gas constant has V as the unit of liters and T has the unit of Kelvin. Thus, option C is correct.
The gas constant in an ideal gas equation has been the value of the energy absorbed by 1 mole of an ideal gas at standard temperature and pressure.
The value of R has been dependent on the units of volume, temperature and pressure of the ideal gas.
The given value of R has been 0.0821 L.atm/mol.K
The unit in gas constant has been L (Liter) for volume (V).
The unit of pressure (P) has been atm.
The unit of temperature (T) has been Kelvin (K).
Thus the gas law constant used by student has V has the unit of liters and T has the unit of Kelvin. Thus, option C is correct.
For more information about the gas constant, refer to the link:
brainly.com/question/24814070
The wood turns into ash and smoke so mass is nor destroyed or created.
