Answer:
Option C (1.2 L) is the correct option.
Explanation:
The given values are:
Pressure,
![P_1=1.9 \ atm](https://tex.z-dn.net/?f=P_1%3D1.9%20%5C%20atm)
![P_2=3.8 \ atm](https://tex.z-dn.net/?f=P_2%3D3.8%20%5C%20atm)
Volume,
![V_1=2.3 \ L](https://tex.z-dn.net/?f=V_1%3D2.3%20%5C%20L)
![V_2=?](https://tex.z-dn.net/?f=V_2%3D%3F)
As we know,
The gas equation is:
⇒ ![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
At constant temperature,
⇒ ![P_1 V_1=P_2 V_2](https://tex.z-dn.net/?f=P_1%20V_1%3DP_2%20V_2)
or,
⇒ ![V_2=\frac{P_1 V_1}{P_2}](https://tex.z-dn.net/?f=V_2%3D%5Cfrac%7BP_1%20V_1%7D%7BP_2%7D)
By substituting the values, we get
⇒ ![=\frac{1.9\times 2.3}{3.8}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1.9%5Ctimes%202.3%7D%7B3.8%7D)
⇒ ![=\frac{4.37}{3.8}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B4.37%7D%7B3.8%7D)
⇒ ![=1.15 \ L](https://tex.z-dn.net/?f=%3D1.15%20%5C%20L)
or,
⇒ ![=1.2 \ L](https://tex.z-dn.net/?f=%3D1.2%20%5C%20L)
A clear chemical compound.
<span>Increasing the surface area helps dissolve more flavoring</span>
Carbon is produced by producers, consumed by consumers, released by consumers, and returned to the air and soil by decomposers.
Taking into account the reaction stoichiometry, 2.405 moles of NaCl are formed when 127.49 grams of Na₂CO₂ reacts with excess of FeCl₃.
<h3>Reaction stoichiometry</h3>
In first place, the balanced reaction is:
2 FeCl+ 3 Na₂CO₂ → Fe₂(CO₃)₃ + 6 NaCl
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- FeCl: 2 moles
- Na₂CO₂: 3 moles
- Fe₂(CO₃)₃: 1 mole
- NaCl: 6 moles
The molar mass of the compounds is:
- FeCl: 91.3 g/mole
- Na₂CO₂: 106 g/mole
- Fe₂(CO₃)₃: 291.7 g/mole
- NaCl: 58.45 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- FeCl: 2 moles ×91.3 g/mole= 182.6 grams
- Na₂CO₂: 3 moles ×106 g/mole= 318 grams
- Fe₂(CO₃)₃: 1 mole ×291.7 g/mole= 291.7 grams
- NaCl: 6 moles ×58.45 g/mole= 350.7 grams
<h3>Mass of NaCl produced</h3>
The following rule of three can be applied: if by reaction stoichiometry 318 grams of Na₂CO₂ form 6 moles of NaCl, 127.49 grams of Na₂CO₂ form how many moles of NaCl?
![moles of NaCl=\frac{127.49 grams of Na_{2} CO_{2} x6 moles of NaCl }{318grams of Na_{2} CO_{2} }](https://tex.z-dn.net/?f=moles%20of%20NaCl%3D%5Cfrac%7B127.49%20grams%20of%20Na_%7B2%7D%20CO_%7B2%7D%20x6%20moles%20of%20NaCl%20%7D%7B318grams%20of%20Na_%7B2%7D%20CO_%7B2%7D%20%7D)
<u><em>moles of NaCl= 2.405 moles</em></u>
Then, 2.405 moles of NaCl are formed when 127.49 grams of Na₂CO₂ reacts with excess of FeCl₃.
Learn more about the reaction stoichiometry:
brainly.com/question/24741074
brainly.com/question/24653699
#SPJ1