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oksian1 [2.3K]
4 years ago
10

Can someone explain this problem? I don't understand it...

Mathematics
1 answer:
Irina18 [472]4 years ago
8 0
1) A function in when there is only one y for that x. (In other words it passes the vertical line test.)

2) Continuous means there are no breaks.

3) For x values less than -2, the graph is going up.

4) Between x values -2 and 8, the graph is going down.

5) After the x value 8, the graph starts to increase again.

6) The graph should only pass the x axis at 5, and only pass the y axis at 2.

Hope this helps.
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Which points are solutions to the linear inequality y < 0.5x + 2
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Answer:

Option 2,4 & 5

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WILL MAEK BRAINLIST
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Answer:

m = -6/7

b = -2

Step-by-step explanation:

m = (y2 - y1)/(x2 - x1) = (-2 - 4)/(0 - (-7)) = -6/7

y = mx + b

m = -6/7

y = -6/7 x + b

Use point (-7, 4).

4 = (-6/7)(-7) + b

4 = 6 + b

b = -2

y = -6/7 x - 2

m = -6/7

b = -2

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3 years ago
(1 point) let a=⟨−4,−3,2⟩a=⟨−4,−3,2⟩. find a unit vector in the same direction as aa.
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A unit vector in the direction of a would be the vector a multiplied by a factor such that the length of vector a is unity.
The magnitude of a is given by:
|a|
=sqrt(4^2+3^2+2^2)   [ I got lazy instead of writing (-4)^2+(-3)^2+2^2]
=sqrt(29).

So the univector is a/sqrt(29), or (-4/sqrt(29),-3/sqrt(29), 2/sqrt(29), or simply (-4,-3,2)/sqrt(29).

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The company June works for pays her 12$ per hour. She works 30 hours per week, and she receives a paycheck every 2 weeks. How do
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