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4 years ago

Can someone explain this problem? I don't understand it...

Mathematics

1 answer:

Irina18 [472]4 years ago

8 0

1) A function in when there is only one y for that x. (In other words it passes the vertical line test.)

2) Continuous means there are no breaks.

3) For x values less than -2, the graph is going up.

4) Between x values -2 and 8, the graph is going down.

5) After the x value 8, the graph starts to increase again.

6) The graph should only pass the x axis at 5, and only pass the y axis at 2.

Hope this helps.

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A triangle has angles that measure 30o, 60o, and 90o. The hypotenuse of the triangle measures 10 inches. Which is the best estim

OverLord2011 [107]

Given: In Δ ABC, ∠B =90° , ∠C = 30° , ∠A = 60° and Hypotenuse AC = 10 inches

It has been described in the attachment.

Now, we shall calculate side AB and BC by using Trigonometric Ratios.

Sin 30° = AB / AC

or, AB = 10 × Sin 30° = 10 × 0.5 = 5 inches

And, Cos 30° = CB / AC

or, CB = 10 × Cos 30° = 10 × 0.866 = 8.66 inches

Now, we shall calculate the perimeter of the given triangle

Perimeter of the triangle = AB + BC + CA

or, = (5.0 + 8.66 + 10.0 ) inches

or, = 23.66 inches ≈ 23.7 inches

Hence, the best estimate for the perimeter of the triangle ( round to the nearest tenth will be 23.7 inches.

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3 years ago

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Is 400 a perfect square ? I’m forgot but I’m pretty sure it isn’t ⚠️⚠️⚠️⚠️⚠️⚠️

uranmaximum [27]

Answer:

Yes, the number 400 is a perfect square. A perfect square is a number that can be expressed as the product of two equal integers.

Step-by-step explanation:

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3 years ago

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An equation of an ellipse is given. y2 = 1 − 3x2 (a) Find the vertices, foci, and eccentricity of the ellipse. vertex (x, y) = (

oksian1 [2.3K]

Answer:

Step-by-step explanation:

Given

$y^2=1-3x^2$

$3x^2+y^2=1$

$\frac{x^2}{(\frac{1}{\sqrt{3}})^2}+\frac{y^2}{1}=1$

therefore it is a vertical ellipse

thus a=1

$b=\frac{1}{\sqrt{3}}$

eccentricity of Ellipse

$e^2=1-\frac{b^2}{a^2}$

$e^2=1-\frac{1}{(\sqrt{3})^2}$

$e^2=1-\frac{1}{3}$

$e^2=\frac{2}{3}$

$e=\sqrt{\frac{2}{3}}$

Focii are $(0,ae)$ and $(0,-ae)$

$ae=1\times \sqrt{\frac{2}{3}}$

thus focii are $(0,\sqrt{\frac{2}{3}})$ & $(0,-\sqrt{\frac{2}{3}})$

(b) Length of major axis $=2a=2\times 1$

length of minor axis $=2b=2\times \sqrt{\frac{2}{3}}=2\cdot \sqrt{\frac{2}{3}}$

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3 years ago

HELPPPPPPPPPPPPPPPPPPPPPP

Helga [31]

To solve this let us try to get x on it's own in the inequality.

-6<3x-12<=9
6<3x<=21
2<x<=7

Now a filled dot indicates <= or >= and empty indicates < or > so we know that the answer must have a filled dot on 7 and an empty dot on 2, with a line in between.

The answer is B, the selected one.

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3 years ago

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A research firm needs to estimate within 3% the proportion of junior executives leaving large manufacturing companies within thr

Y_Kistochka [10]

Answer:

972 junior executives should be surveyed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.