How many grams are in 0.375 mol KBr?
1 answer:
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Answer : The correct option is, (D) 100 times the original content.
Explanation :
As we are given the pH of the solution change. Now we have to calculate the ratio of the hydronium ion concentration at pH = 5 and pH = 3
As we know that,
The hydronium ion concentration at pH = 5.
..............(1)
The hydronium ion concentration at pH = 3.
................(2)
By dividing the equation 1 and 2 we get the ratio of the hydronium ion concentration.
From this we conclude that when the pH of a solution changes from a pH of 5 to a pH of 3, the hydronium ion concentration is 100 times the original content.
Hence, the correct option is, (D) 100 times the original content.