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Diano4ka-milaya [45]
3 years ago
5

A weak acid is titrated with 0.1236 M NaOH. From the titration curve you determine that the equivalence point occurs after exact

ly 12.42 mL of NaOH have been added. What is the volume of NaOH at the half-equivalence point (a.k.a. the midpoint)
Chemistry
1 answer:
MrRa [10]3 years ago
7 0

<u>Answer:</u> The volume of NaOH required at the half-equivalence point is 6.21 mL

<u>Explanation:</u>

The chemical equation for the reaction of a weak acid with NaOH follows:

HA+ NaOH\rightarrow NaA+H_2O

From the equation, we can say that NaOH and weak acid is present in a 1 : 1 ratio.

We are given:

Volume of NaOH required at equivalence point = 12.42 mL

The volume of NaOH required at half-equivalence point will be = \frac{12.42mL}{2}=6.21mL

Hence, the volume of NaOH required at the half-equivalence point is 6.21 mL

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An unknown compound contains only carbon, hydrogen, nitrogen, and oxygen. Complete combustion of a 2.77 g sample of the compound
alisha [4.7K]

The molecular formula of the unknown compound is determined as  C₉H₁₁NO₂.

<h3>Molecular formula of the compound</h3>

The molecular formula is calculated as follows;

CHNO  +  O₂ ------------> CO₂  + H₂O

Mass of carbon, C:  = (6.64 x 12)/44 = 1.81 g in 2.77 g sample

Mass of hydrogen, H: = (1.67 x 2)/18 = 0.186 g in 2.77 g sample

Mass of Nitrogen, N: = (2.77 x 0.143)/1.69 = 0.234 g

Mass of oxygen, O:  = 2.77 g - 1.81 g - 0.186 g - 0.234 g = 0.54 g

<h3>molar ratio of the elements: </h3>

C = 1.81 g = 0.15 mol

H = 0.186 g = 0.186 mol

N = 0.234 g = 0.017 mol

O = 0.54 g = 0.0337 mol

divide through with the smallest number of moles (0.017 mol);

C = 9

H = 11

N = 1

O = 2

Molecular formula = C₉H₁₁NO₂

Check the molar mass of the compound = (9 x 12) + (11 x 1) + (14) + (2 x 16) = 165 g/mol

Thus, the molecular formula of the unknown compound is determined as  C₉H₁₁NO₂.

Learn more about molecular mass here: brainly.com/question/21334167

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