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AleksandrR [38]
3 years ago
5

From a scientific viewpoint, why do many desert dwellers elect to wear white or light-colored garments

Chemistry
1 answer:
alexandr1967 [171]3 years ago
7 0
Darker colors absorb sunlight more, so it will become hotter. Lighter colored clothes will better reflect sun so they will be less hot.

Hope that helped
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The ratio of x to y is 4 to 12. Fill in numbers to<br>form a table with the given ratio,​
murzikaleks [220]

Answer:

Explanation:

x                                     y

4                                     12

8                                     24

12                                   36

16                                   48

20                                  60

           

4 0
3 years ago
Calculate the molar concentration of the Cl⁻ ions in 0.92 M MnCl2(aq).
scZoUnD [109]
MnCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MnCl2 that dissolves.
MnCl2(s) --> Mn+(aq) + 2 Cl⁻(aq)
            [Cl⁻] = 0.92 mol MnCl2/1L × 2 mol Cl⁻ / 1 mol MnCl2 = 1.8 M
The answer to this question is [Cl⁻] = 1.8 M
4 0
3 years ago
What hypothesis led to the discovery of the proton?
Lana71 [14]

When a neutral hydrogen atom loses an electron, a positively-charged particle should remain.

4 0
2 years ago
Read 2 more answers
Consider a mixture of soil and water and compare it to a colloid, such as milk. Which property best differentiates these two mix
mezya [45]
There are many differentiates between them. Like if you standing these two mixture, the soil and water will separate while milk will not. And colloid have tyndall effect while soil and water doesn't have.
7 0
2 years ago
After balancing the following reaction under acidic conditions, how many mole equivalents of water are required and on which sid
nordsb [41]

Answer:

d. 8 moles of H2O on the product side

Explanation:

Hello,

In this case, we need to balance the given redox reaction in acidic media as shown below:

MnO_4^{1-} (aq) + Cl^{1-} (aq) \rightarrow  Mn^{2+} (aq) + Cl_2 (g)\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq) + Cl^{1-} (aq) \rightarrow  Mn^{2+} (aq) + Cl_2 (g)\\\\\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O\\\\2Cl^{1-}\rightarrow Cl_2^0+2e^-\\\\2*[(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O]\\\\5*[2Cl^{1-}\rightarrow Cl_2^0+2e^-]\\\\\\\\2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10e^- \rightarrow 2Mn^{2+}+8H_2O\\\\10Cl^{1-}\rightarrow 5Cl_2^0+10e^-\\

Then, we add the half reactions:

2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10Cl^{1-} \rightarrow 2Mn^{2+}+8H_2O+5Cl_2^0

Thereby, we can see d. 8 moles of H2O on the product side.

Best regards.

4 0
2 years ago
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