The compounds are arranged from the least heat of combustion to the highest (in order of increasing heat of combustion).
Propane--> butane --> pentane.
Explanation:
Hydrocarbons are compounds which contains carbon and hydrogen only. Alkane is called a saturated hydrocarbon because all four bonds of carbon are single bonds. Examples of alkanes include: pentane, propane and butane. One of the chemical properties of alkanes includes combustion reaction.
In COMBUSTION REACTION, alkanes burns in air (oxygen) to produce carbon dioxide and water.The heat released on complete combustion of one mole of a substance is called HEAT OF COMBUSTION.
The heat of combustion of saturated hydrocarbon ( alkanes) increases with increase in number of carbon atoms in a molecule. This is due to more carbon available for burning and more number of bonds undergoing changes. Therefore in the arrangement of the given compounds, PENTANE has the highest heat of combustion while PROPANE is the least.
The detailed solution is shown in the image attached. First we must work out the balanced reaction equation because accurate solution of the problem must be based on the stoichiometry of the reaction. From the given concentration and volume of reactants, we calculate the amount of substance reacted hence identify the limiting reactant. Lastly we use simple proportion to obtain the theoretical yield of the precipitate. This is now used to calculate the actual yield as shown in the solution attached.
The molar mass is the mass of all atoms in a molecule we first obtain the atomic weights from the individual elements in a periodic table then count the number of atoms and multiply it by the individual atomic masses
