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pogonyaev
3 years ago
14

Rank the following compounds in order of increasing heat of combustion. Be sure to answer all parts. Drag each item to the corre

ct box. A) pentane B) propane C) butane
Chemistry
1 answer:
vfiekz [6]3 years ago
7 0

Answer:

The compounds are arranged from the least heat of combustion to the highest (in order of increasing heat of combustion).

Propane--> butane --> pentane.

Explanation:

Hydrocarbons are compounds which contains carbon and hydrogen only. Alkane is called a saturated hydrocarbon because all four bonds of carbon are single bonds. Examples of alkanes include: pentane, propane and butane. One of the chemical properties of alkanes includes combustion reaction.

In COMBUSTION REACTION, alkanes burns in air (oxygen) to produce carbon dioxide and water.The heat released on complete combustion of one mole of a substance is called HEAT OF COMBUSTION.

The heat of combustion of saturated hydrocarbon ( alkanes) increases with increase in number of carbon atoms in a molecule. This is due to more carbon available for burning and more number of bonds undergoing changes. Therefore in the arrangement of the given compounds, PENTANE has the highest heat of combustion while PROPANE is the least.

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The given chemical reaction is:

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Initial conc.    2.4\times 10^{-2}          0             0

At eqm.          (2.4\times 10^{-2}-x)   x              x

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