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Rufina [12.5K]
3 years ago
15

How do you find the force of gravity?

Physics
1 answer:
devlian [24]3 years ago
7 0
1<span>Define the equation for the force of gravity that attracts an object, <span>Fgrav = (Gm1m2)/d2</span>
2. </span>Use the proper metric units.
3. Determine the mass of the object in question.
4. <span>Measure the distance between the two objects
5. </span><span>Solve the equation
</span>


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The following table lists the work functions of a few commonmetals, measured in electron volts.
steposvetlana [31]

Answer:

Lithium

Explanation:

The equation for the photoelectric effect is

\frac{hc}{\lambda}= \phi + K_{max}

where

\frac{hc}{\lambda} is the energy of the incident photon, with

h being the Planck constant

c is the speed of light

\lambda is the wavelength of the photon

\phi is the work function of the metal (the minimum energy needed to extract the photoelectron from the metal)

K_{max} is the maximum kinetic energy of the emitted photoelectrons

In this problem, we have

\lambda= 190 nm = 1.9\cdot 10^{-7}m is the wavelength of the incident photon

K_{max}=4.0 eV is the maximum kinetic energy of the electrons

First of all we can find the energy of the incident photon

E=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{1.90\cdot 10^{-7} m}=1.05\cdot 10^{-18} J

Converting into electronvolts,

E=\frac{1.05\cdot 10^{-18} J}{1.6\cdot 10^{-19} J/eV}=6.6 eV

So now we can re-arrange the equation of the photoelectric effect to find the work function of the metal

\phi = E-K_{max}=6.6 eV - 4.0 eV=2.6 eV

So the metal is most likely Lithium, which has a work function of 2.5 eV.

3 0
3 years ago
Can someone help my with my Physics lab pleaseeeee
den301095 [7]

Answer:

whats the question

Explanation:

where your question

4 0
3 years ago
Based on their locations on the periodic table, which two elements would you
Nat2105 [25]

Answer:

i think it would be B. Aluminum, Al and D. Boron, B

Explanation:

since they're both in group 13 and they forms a 3+ ion

6 0
3 years ago
Read 2 more answers
Which model shows how an image appears to a person when they look through a concave lens?
slava [35]
What models are you talking about
7 0
2 years ago
Equal currents of magnitude I travel into the page in wire M and out of the page in wire N. The direction of the magnetic field
mario62 [17]

Answer:

<em>The direction of the magnetic field on point P, equidistant from both wires, and having equal magnitude of current flowing through them will be pointed perpendicularly away from the direction of the wires.</em>

Explanation:

Using the right hand grip, the direction of the magnet field on the wire M is counterclockwise, and the direction of the magnetic field on wire N is clockwise. Using this ideas, we can see that the magnetic flux of both field due to the currents of the same magnitude through both wires, acting on a particle P equidistant from both wires will act in a direction perpendicularly away from both wires.

5 0
3 years ago
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