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4 years ago

The position of a full moon is located

Physics

2 answers:

Otrada [13]4 years ago

7 0

The position of the full moon will be located opposite the sun.

marissa [1.9K]4 years ago

4 0

Answer:

opposite the sun. between the Earth and the sun. rising perpendicular to the sun.

Explanation:

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What is the correct formula for of the weight w of an object? assume that its mass is m, the magnitude of its acceleration is a,

Vsevolod [243]

Weight = Mass × Acceleration

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3 years ago

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Which of the following is n application of electromagnetic field? A. D. C motor B. A.C motor C. Moving coil galvanometer D. All

Zanzabum

Answer:

c or d

Explanation:

it just is thats how it is

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3 years ago

Two 10-cm-diameter metal plates 1.0 cm apart are charged to {12.5 nC. They are suddenly connected together by a 0.224-mm- diamet

Alekssandra [29.7K]

Answer:

(a).The maximum current in the wire is $4.217\times10^{5}\ A$ .

(b). The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c).The current also decrease with time.

(d). The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

Explanation:

Given that,

Diameter of metal plates = 10 cm

Distance between the plates = 1.0 cm

Charged = 12.5 nC

Diameter of copper wire = 0.224 mm

We need to calculate the cross section area of the plates

Using formula of area

$A=\pi r^2$

Put the value into the formula

$A=\pi\times(5\times10^{-2})^2$

$A=7.85\times10^{-3}\ m^2$

We need to calculate the capacitor

Using formula of capacitor

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times7.85\times10^{-3}}{1.0\times10^{-2}}$

$C=6.94\times10^{-12}\ F$

We need to calculate the resistance of the wire

Using formula of resistivity

$R=\dfrac{\rho l}{A}$

Put the value into the formula

$R=\dfrac{1.7\times10^{-8}\times1.0\times10^{-2}}{\pi\times(0.1125\times10^{-3})^2}$

$R=4.27\times10^{-3}\ \Omega$

We need to calculate the voltage

Using formula of charge

$q=CV$

$V=\dfrac{q}{C}$

Put the value into the formula

$V=\dfrac{12.5\times10^{-9}}{6.94\times10^{-12}}$

$V=1.801\times10^{3}\ V$

(a). We need to calculate the current

Using formula of current

$I=\dfrac{V}{R}$

$I=\dfrac{1.801\times10^{3}}{4.27\times10^{-3}}$

$I=421779.85\ A$

$I=4.217\times10^{5}\ A$

(b). We need to calculate the electric field

Using formula of electric field

$E=\dfrac{kq}{r^2}$

Put the value into the formula

$E=\dfrac{9\times10^{9}\times12.5\times10^{-9}}{(1.0\times10^{-2})^2}$

$E=11.2\times10^{5}\ N/C$

The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c). In this case, the voltage between the capacitor plates decreases as the charge decreases with time.

The current is directly proportional to the voltage between the plates .

Hence, The current also decrease with time.

(d). We need to calculate the total amount of energy dissipated in the wire

Using formula of energy

$E=\dfrac{1}{2}CV^2$

Put the value into the formula

$E=\dfrac{1}{2}\times6.94\times10^{-12}\times(1.801\times10^{3})^2$

$E=1.126\times10^{-5}\ J$

The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

Hence, (a).The maximum current in the wire is $4.217\times10^{5}\ A$ .

(b). The electric field in the wire is $11.2\times10^{5}\ N/C$ .

(c).The current also decrease with time.

(d). The total amount of energy dissipated in the wire is $1.126\times10^{-5}\ J$

8 0

3 years ago

Which has more momentum: a 20,000 kg cement truck traveling at 5 m/s or a 1000 kg race car traveling at 90 m/s

Maurinko [17]

Hi there!

Recall the equation for momentum:
$\large\boxed{p = mv}$

p = linear momentum (kgm/s)
m = mass (kg)

v = velocity (m/s)

We can calculate each object's momentum and compare.

Cement truck:
$p = 20000 \cdot 5 = 100000kg\frac{m}{s}$

Race car:
$p = 1000 \cdot 90 = 90000 kg\frac{m}{s}}$

<u>Since 100,000 > 90,000, the cement truck has the greater momentum.</u>

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3 years ago

If you carry out an experiment measuring the weight and mass of objects in one particular location on the earth, what relation w

mario62 [17]

<span>Weight is directly proportional to mass.</span>

4 0

3 years ago

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