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Usimov [2.4K]
3 years ago
15

This image below shows a ship using sonar to map the seafloor. pls help i need this :(

Physics
1 answer:
Umnica [9.8K]3 years ago
5 0

Answer:

d and i think a?

Explanation:

im so sorry if its wrong

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The Mass of the Sun is 1.989 × 10^30 kg. The speed of light is 3 x 10^8 m/s. Assuming the Sun is 75% hydrogen, how much Energy c
bogdanovich [222]

Answer:

E = 13.428 \times 10^{46} J

Explanation:

Mass of the Sun = 1.989 \times 10^{30} Kg

Amount of Hydrogen = 75% of Mass of Sun,

thus mass of Hydrogen (m) in the Sun is,

m = 1.989 \times 10^{30} \times \frac{75}{100}

m = 1.492 \times 10^{30}

Speed of Light (c) = 3 \times 10^{8} m/s

Thus, energy(E) produced if whole of hydrogen is converted into energy,

E = mc²

E = 1.492 \times 10^{30} \times (3 \times 10^{8} )^{2}

E = 1.492 \times 9 \times 10^{46}

E = 13.428 \times 10^{46} J

8 0
2 years ago
Will you travel in 3.0 minutes running at a rate of 6.0 m/s
aalyn [17]

Answer:

1080 meters

Explanation:

60sec in 1 minute

So, 3x60=180

  • 6m/s (one second is 6 meters)

So, 6x180=1080 meters

5 0
3 years ago
A bungee cord can stretch, but it is never compressed. When the distance between the two ends of the cord is less than its unstr
Ksju [112]

Answer:

Explanation:

Given that

g=9.8m/s²

The spring constant is

k=50N/m

The length of the bungee cord is

Lo=32m

Height of bridge which one end of the bungee is tied is 91m

A steel ball of mass 92kg is attached to the other end of the bungee.

The potential energy(Us) of the steel ball before dropped from the bridge is given as

P.E= mgh

P.E= 92×9.8×91

P.E= 82045.6 J

Us= 82045.6 J

Potential energy)(Uc) of the cord is given as

Uc= ½ke²

Where 'e' is the extension

Then the extension is final height extended by cord minus height of cord

e=hf - hi

e=hf - 32

Uc= ½×50×(hf-32)²

Uc=25(hf-32)²

Using conservation of energy,

Then,

The potential energy of free fall equals the potential energy in string

Uc=Us

25(hf-32)²=82045.6

(hf-32)² = 82045.6/25

(hf-32)²=3281.825

Take square root of both sides

√(hf-32)²=√(3281.825)

hf-32=57.29

hf=57.29+32

hf=89.29m

We neglect the negative sign of the root because the string cannot compressed

3 0
3 years ago
In outer space, a piece of rock continues moving at the same velocity for
Ray Of Light [21]

The absence of external force in the outer space, allows the piece of rock to continue moving at the same velocity for thousands of years.

<h3>Absence of external force on the outer space</h3>

The outer space is almost an absolute vacuum, because it's nearly empty. There is no matter such as air in the outer space that will provide an external force needed to change the velocity of the piece of rock.

From Newton's first law of motion, an object in a state of rest or uniform motion in a straight line, will continue in that state unless it is acted upon by an external force.

Thus, the absence of external force in the outer space, allows the piece of rock to continue moving at the same velocity for thousands of years.

Learn more about outer space here: brainly.com/question/24701339

7 0
2 years ago
If the pitched ball was traveling 77 mph before stanton's bat hit it and 120 mph after his bat hit it, by what amount did the sp
Mice21 [21]

here we will use the concept of Newton's III law

as per Newton's III law the impulse given to the ball is same as the impulse lost by the bat

So here we will say

impulse gain by the ball = impulse lost by the bat

m_1(v_f - v_i) = m_2(\Delta v)

given that

m_1 = 5 ounce

m_2 = 32 ounce

For ball the change in speed will be

v_f - v_i = (120 - 77)mph

now from above equation

5\times (120 - 77) = 32 \times \Delta v

\Delta v = 6.72 mph

so speed of bat will decrease by 6.72 mph

3 0
3 years ago
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