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TiliK225 [7]
3 years ago
9

Both production lines can produce all the different types of nozzles. The bronze machines needed for the bronze sprinklers requi

re four operators and can produce up to 15,000 sprinklers. The plastic injection molding machine needed for the plastic sprinklers requires five operators and can produce up to 240,000 sprinklers. Three bronze machines and only one injection molding machine are available. What are the capacity requirements for the next four years
Business
1 answer:
dsp733 years ago
5 0

Answer:

Demand for plastic sprinklers for year 1 Year 2 Year 3 and Year 4 is 98 (33 + 14 + 51) , 111 , 133, 136.  

Explanation:

The Production line capacity requirement for the next four years will be equal to the demand for the next four years. The production line needs to meet the annual demand for the plastic sprinklers. The production line is extended and economies of scale is introduced with helps the company save additional cost of extension in the production line.

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A broker's listing agreement specifies that a 5½% commission is to be paid on the sale price. The sales associate for the firm
tino4ka555 [31]

The amount that the sales associate earn if she sells the property for $369,000 is $11,162.25.

Sales associate's commission

First step  find the total commission

Total commission=$369,000 sale price × .055 rate

Total commission= $20,295

Second step find the sales associate's commission

Sales associate's commission=$20,295 total commission × .55 split

Sales associate's commission=$11,162.25

Inconclusion the amount that the sales associate earn if she sells the property for $369,000 is $11,162.25.

Learn more about sales associate's commission here:brainly.com/question/930797

5 0
1 year ago
In October, Glazier Inc. reports 42,000 actual direct labor hours, and it incurs $194,000 of manufacturing overhead costs. Stand
Olin [163]

Answer:

$18,000 F

Explanation:

Actual overhead– Overhead Budgeted=

Overhead Controllable Variance

Actual overhead=$194,000

Overhead Budgeted=$212,000

$194,000–$212,000

=$18,000 F

(40,000 ×$3.80) + $60,000

=$152,000+$60,000

= $212,000

Therefore the manufacturing overhead controllable variance is $18,000 F

3 0
3 years ago
Santorino Company produces two models of a component, Model K-3 and Model P-4. The unit contribution margin for Model K-3 is $6;
tresset_1 [31]

Answer:

Contribution per unit of scare resource (in hour) = $24 per hour

Explanation:

The question falls under the limiting factor analysis

<em>When a business is faced with a problem of shortage of a resource which can be used to produced more than one product type, to maximize the use of the resource , the business should allocate it for production purpose in such a way that </em><em>it maximizes the contribution per unit of the scare resource.</em>

Therefore Santario Company should allocate the machine hours to maximize the contribution per unit of machine hour.

Contribution per unit of scare resource is determine as follows:

Contribution per unit of scare resource for Model K-3

Contribution per unit of Model K-3 = $6

Machine time per unit =  15 minutes

<em>Contribution per unit of scare resource in minutes</em>

=Contribution per unit/Machine time per unit

= 46/15 minutes

= $0.4 per minute

Contribution per unit of scare resource (in hour)

$0.4 per minutes× 60

= $24 per hour

7 0
3 years ago
Please help best gets brainiest
Zepler [3.9K]
To help maintain a balanced personal budget sounds like the answer. Hope it helps! :-)
6 0
3 years ago
A publisher reports that 55% of their readers own a particular make of car. a marketing executive wants to test the claim that t
Dominik [7]

Based on the percentage of readers who own a particular make of the car and the random sample, we can infer that there is sufficient evidence at a 0.02 level to support the executive claim.

<h3>What is the evidence to support the executive's claim?</h3>

The hypothesis is:

Null hypothesis : P = 0.55

Alternate hypothesis : P ≠ 0.55

We then need to find the test statistic:

= (Probability found by marketing executive - Probability from publisher) / √( (Probability from publisher x (1 - Probability from publisher))/ number of people sampled

= (0.46 - 0.55) / √(( 0.55 x ( 1 - 0.55)) / 200

= -2.56

Using this z value as the test statistic, perform a two-tailed test to show:

= P( Z < -2.56) + P(Z > 2.56)

= 0.0052 + 0.0052

= 0.0104

The p-value is 0.0104 which is less than the significance level of 0.02. This means that we reject the null hypothesis.

The Marketing executive was correct.

Find out more on the null and alternate hypothesis at brainly.com/question/25263462

#SPJ1

8 0
1 year ago
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