The amount that the sales associate earn if she sells the property for $369,000 is $11,162.25.
Sales associate's commission
First step find the total commission
Total commission=$369,000 sale price × .055 rate
Total commission= $20,295
Second step find the sales associate's commission
Sales associate's commission=$20,295 total commission × .55 split
Sales associate's commission=$11,162.25
Inconclusion the amount that the sales associate earn if she sells the property for $369,000 is $11,162.25.
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Answer:
$18,000 F
Explanation:
Actual overhead– Overhead Budgeted=
Overhead Controllable Variance
Actual overhead=$194,000
Overhead Budgeted=$212,000
$194,000–$212,000
=$18,000 F
(40,000 ×$3.80) + $60,000
=$152,000+$60,000
= $212,000
Therefore the manufacturing overhead controllable variance is $18,000 F
Answer:
Contribution per unit of scare resource (in hour) = $24 per hour
Explanation:
The question falls under the limiting factor analysis
<em>When a business is faced with a problem of shortage of a resource which can be used to produced more than one product type, to maximize the use of the resource , the business should allocate it for production purpose in such a way that </em><em>it maximizes the contribution per unit of the scare resource.</em>
Therefore Santario Company should allocate the machine hours to maximize the contribution per unit of machine hour.
Contribution per unit of scare resource is determine as follows:
Contribution per unit of scare resource for Model K-3
Contribution per unit of Model K-3 = $6
Machine time per unit = 15 minutes
<em>Contribution per unit of scare resource in minutes</em>
=Contribution per unit/Machine time per unit
= 46/15 minutes
= $0.4 per minute
Contribution per unit of scare resource (in hour)
$0.4 per minutes× 60
= $24 per hour
To help maintain a balanced personal budget sounds like the answer. Hope it helps! :-)
Based on the percentage of readers who own a particular make of the car and the random sample, we can infer that there is sufficient evidence at a 0.02 level to support the executive claim.
<h3>What is the evidence to support the executive's claim?</h3>
The hypothesis is:
Null hypothesis : P = 0.55
Alternate hypothesis : P ≠ 0.55
We then need to find the test statistic:
= (Probability found by marketing executive - Probability from publisher) / √( (Probability from publisher x (1 - Probability from publisher))/ number of people sampled
= (0.46 - 0.55) / √(( 0.55 x ( 1 - 0.55)) / 200
= -2.56
Using this z value as the test statistic, perform a two-tailed test to show:
= P( Z < -2.56) + P(Z > 2.56)
= 0.0052 + 0.0052
= 0.0104
The p-value is 0.0104 which is less than the significance level of 0.02. This means that we reject the null hypothesis.
The Marketing executive was correct.
Find out more on the null and alternate hypothesis at brainly.com/question/25263462
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