Acids and bases are fairly important for the fact that they are very essential to the human body. As well as they balance the Ph levels in our body. You can use acids and bases to nurtralize eachother aswell
Elements combine in three general ways. In<u> ionic</u> compounds, electrons are transferred from one element to the other, whereas in <u>covalent </u>compounds, electrons are shared between atoms. Third, in <u>metallic </u>bonding, electrons are shared between a large number of atoms in an electron sea.
Ionic compounds are compounds in which a free electron is transferred to another atom and a bond is formed. Ionic bonds occur in metal ions.
In liquid compounds, covalent bonds are formed. In covalent bonds, electrons are shared with each other,
The third type of bond is the metallic bond. In this type of bond, atoms are packed tightly and a free electron pool travels in between them.
To learn more ionic bonds, click here:
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Answer:
Because energy is conserved, the kinetic energy of a block at the bottom of a frictionless
ramp is equal to the gravitational potential energy of the block at the top of the ramp. This
value is proportional to the square of the block’s velocity at the bottom of the ramp.
Therefore, the block’s final velocity depends on the height of the ramp but not the steepness
of the ramp
Explanation:
Answer:
Solution A that will form a precipitate with Ksp = 2.3 x 10−4
Explanation:
Li₃PO₄ ⇄ 3 Li⁺(aq) + PO₄³⁻(aq)
3S S
Where S = Solubility(mole/lit) and Ksp = Solubility product
⇒ Ksp = (3S)³ x (S)
⇒ 27S⁴ = 2.3x10−4
⇒ S = 0.05 mol/lit
Concentration of Li₃PO₄ precipitate = 0.05
<u>Solution A </u>
0.500 lit of a 0.3 molar LiNO₃ contains 0.5 x 0.3 = 0.15 mole
0.4 lit of a 0.2 molar Na₃PO₄ contains = 3 x 0.4 x 0.2 = 0.24 mole
3 LiNO₃ + Na₃PO₄ → 3 NaNO₃ + Li₃PO₄
(Mole/Stoichiometry) 
= 0.05 = 0.24
Since from (Mole/Stoichiometry) ratio we can conclude that LiNO₃ is limiting reagent.
So concentration of Li₃PO₄ is equal to 0.05.
Answer:
The concentration of this sodiumhydroxide solutions is 0.50 M
Explanation:
Step 1: Data given
Mass of sodium hydroxide (NaOh) = 8.0 grams
Molar mass of sodium hydroxide = 40.0 g/mol
Volume water = 400 mL = 0.400 L
Step 2: Calculate moles NaOH
Moles NaOH = mass NaOH / molar mass NaOH
Moles NaOH = 8.0 grams / 40.0 g/mol
Moles NaOh = 0.20 moles
Step 3: Calculate concentration of the solution
Concentration solution = moles NaOH / volume water
Concentration solution = 0.20 moles / 0.400 L
Concentration solution = 0.50 M
The concentration of this sodiumhydroxide solutions is 0.50 M
