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gizmo_the_mogwai [7]
3 years ago
13

Write the reaction from the word equation and then balence the equation

Chemistry
1 answer:
Mars2501 [29]3 years ago
4 0
<h3>Answer:</h3>

Ni + Pb(NO₃)₂ → Ni(NO₃)₃ + Pb

<h3>Explanation:</h3>

We are required to write a balanced equation from the word equation;

  • Nickel reacts with lead nitrate (II) to produce nickel(III) nitrate and lead
  • The equation will be written by writing the symbols of the reactants and products.

That is;

Ni + Pb(NO₃)₂ → Ni(NO₃)₃ + Pb

We then balance the equation;

  • To balance the equation, we put appropriate coefficients on reactants and products, so that the number of atoms of each element is equal on both sides of the equation.
  • Thus, the balanced equation will be;

2Ni + 3Pb(NO₃)₂ → 2Ni(NO₃)₃ + 3Pb

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Gaseous hydrogen and oxygen can be prepared in the laboratory from the decomposition of gaseous water. The equation for the reac
nata0808 [166]

Answer:

m_{O_2}=87.2gO_2

Explanation:

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In this case, given the chemical reaction, we can compute the grams of oxygen by using the 98.2 g of water via the 2:1 mole ratio between them, the molar mass of water that is 18.02 g/mol, the molar mass of gaseous oxygen that is 32.00 g/mol and the following stoichiometric procedure relating the given information:

m_{O_2}=98.2gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{1molO_2}{2molH_2O}*\frac{32.00gO_2}{1molO_2}   \\\\m_{O_2}=87.2gO_2

In which the result is displayed with three significant figures because the given mass of water 98.2 g, has three significant figures too.

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2 years ago
The hardest known mineral is _____.<br> topaz<br> talc<br> diamond<br> graphite
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Suppose a platinum atom in the oxidation state formed a complex with two chloride anions and two ammonia molecules. Write the ch
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Answer: Pt(Cl)2(NH3)2

Explanation:

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A metal coin has certain properties that can be measured if the coin were to go from earth to moon the coins will remain the sam
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A 1.25 g sample of aluminum is reacted with 3.28 g of copper (II) sulfate. What is the limiting reactant?
KengaRu [80]

Answer:

d. Copper (II) sulfate

Explanation:

Given data:

Mass of Al = 1.25 g

Mass of CuSO₄ = 3.28 g

What is limiting reactant = ?

Solution:

Chemical equation:

2Al + 3CuSO₄   →   Al₂ (SO₄)₃ + 3Cu

Number of moles of Al:

Number of moles = mass/molar mass

Number of moles = 1.25 g/ 27 g/mol

Number of moles = 0.05 mol

Number of moles of CuSO₄:

Number of moles = mass/molar mass

Number of moles = 3.28 g/ 159.6 g/mol

Number of moles = 0.02 mol

now we will compare the moles of reactant with product.

               Al           :           Al₂ (SO₄)₃

                 2          :             1

               0.05       :          1/2×0.05=0.025 mol

                Al           :            Cu

                 2            :              3

               0.05         :            3/2×0.05 = 0.075 mol

         CuSO₄           :           Al₂ (SO₄)₃

                3             :             1

               0.02         :          1/3×0.02=0.007 mol

         CuSO₄           :            Cu

               3               :              3

               0.02         :              0.02

Less number of moles of reactants are produced by CuSO₄ thus it will act as limiting reactant.

4 0
3 years ago
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