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3 years ago

Salts and acids are examples of inorganic compounds called _____, which dissociate in water to release ions.

Chemistry

2 answers:

g100num [7]3 years ago

8 0

Salts and acids are examples of inorganic compounds called Electrolytes which dissociate in water to release ions.

<h2>Further Explanation: </h2><h3>A compound </h3>

A compound is a substances that contains two or more different atoms that are bonded together.
When the atoms are similar the substance is known as a molecule, therefore not all molecules are compounds.

<h3>Electrolytes</h3>

Electrolytes are substances that are either in molten or aqueous form that discharged by passing electric current through them. They dissociate into ions while in molten or solution form.
These compounds are made of mobile ions which are responsible for the conduction of electricity.
Examples includes, soluble salts, ionic compounds, acids, and bases etc.

A salt is a substance that is formed when an acid reacts with a base or when the hydrogen part of acid is replaced by metal ion or an ammonium ion.

<h3>Ionic compounds </h3>

Ionic compounds are compounds that contain ions. They are as a result of ionic bonding between a metal atom and a non-metal atom.
During ionic bonding formation the metallic atom looses electrons while the non-metallic atom gains electrons.
Ionic compounds contains both negatively charged ion(anion) and positively charged ion (cation).
Examples of ionic compounds, NaCl, LiF, KCl, Cs2S, KBr, PbS etc.
Most ionic compounds may act as electrolytes.

Keywords: Compound, electrolytes, salts, ionic compounds, soluble acids, bases.

<h3>Learn more about: </h3>

Compound: brainly.com/question/10052458
Electrolytes: brainly.com/question/4053091
Electrolysis: brainly.com/question/11868966
Ionic compounds: brainly.com/question/10052458

Level: High school

Subject: Chemistry

Topic: Electrolysis

Sub-topic: Electrolytes.

Blizzard [7]3 years ago

4 0

Answer:

Salts and acids are examples of inorganic compounds called <u><em>electrolytes</em></u>.

Explanation:

Electrolytes are the substances which dissociates into ions when dissolved in water and due to this they are able to conduct electric current through them. These compounds in solid form does not conduct electricity due to the absence of free ions.

For example: Sodium chloride , sulfuric acid etc.

$NaCl(aq)\righarrow = Na^+(aq)+Cl^-(aq)$

$H_2SO_4(aq)\rightarrow SO_4^{2-}(aq)+2H^+(aq)$

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PLEASE HELP <3

frutty [35]

In order for carbon to be stable and have 8 electrons, it must make 4 total covalent bonds.

In prefer for oxygen to be stable and have 8 electrons, it must make 2 covalent bonds.

So, we can deduce that CO2 looks like this:

O=C=O

This molecule has two double bonds.

Pssst...Can I get a brainliest?

8 0

3 years ago

How many grams of Chromium can be formed when 150 grams of

valentinak56 [21]

Answer: 104 g

Explanation: reaction Cr2O3 + 3 H2 ⇒ 2 Cr + 3 H2O

M(Cr2O3) = 150 g/mol, so n = m/M = 1.0 mol

Number of moles of H2 should be 3.0 moles and

It is much greater (150 g / 2.016 g/mol)

1 mol Cr2O3 produces 2 mol Cr.

Mass m= 2.0 mol· 52g/mol= 104 g

6 0

2 years ago

A sample compound contains 5.723g Ag, 0.852g S and 1.695g O. Determine its empirical formula.

Lubov Fominskaja [6]

Answer:

$Ag_2SO_4$

Explanation:

Formula for the calculation of no. of Mol is as follows:

$mol=\frac{mass\ (g)}{molecular\ mass}$

Molecular mass of Ag = 107.87 g/mol

Amount of Ag = 5.723 g

$mol\ of\ Ag=\frac{5.723\ g}{107.87\ g/mol} =0.05305\ mol$

Molecular mass of S = 32 g/mol

Amount of S = 0.852 g

$mol\ of\ S=\frac{0.852\ g}{32\ g/mol} =0.02657\ mol$

Molecular mass of O = 16 g/mol

Amount of O = 1.695 g

$mol\ of\ O=\frac{1.695\ g}{16\ g/mol} =0.10594\ mol$

In order to get integer value, divide mol by smallest no.

Therefore, divide by 0.02657

$Ag, \frac{0.05305}{0.02657} \approx 2$

$S, \frac{0.02657}{0.02657} \approx 1$

$O, \frac{0.10594}{0.02657} \approx 4$

Therefore, empirical formula of the compound = $Ag_2SO_4$

7 0

3 years ago

Read 2 more answers

What is the ending of the electron configuration of each element in group 4?

bogdanovich [222]

<span>because p6 will be the group 8. You have to count the 2 electrons from the "s" block that are Group I and Group II Group I s1 Group II s2 Group III s2 p1 Group IV s2 p2 Group V s2 p3 Group VI s2 p4 Group VII s2 p5 Group VIII s2 p6</span>

6 0

3 years ago

What is the oxidation state of an individual phosphorus atom in P O 3 3−?

Tju [1.3M]

-3 - 3(-2) = +3
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4 0

2 years ago