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siniylev [52]
3 years ago
15

How consumers affect which goods and services are produced.

Chemistry
1 answer:
oksano4ka [1.4K]3 years ago
6 0
Consumers affect the goods and services produced through:

- The more we buy something the more popular it is and the more of it is made

- The products that is less popular and less made are because we don't buy them

- When we buy more of something the more expensive the product or service will be

- When we buy less of something the more cheaper that product or service will be

Please vote my answer branliest! Thanks.

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How many different compounds are possible, changing only the cis/trans arrangements around these two double bonds?
insens350 [35]
Check the attached file for the answer.

3 0
2 years ago
14. Which of the following is produced when propane (C3H8) is combusted completely? (2 points)
Ymorist [56]

The following is produced when propane (C₃H₈) is combusted completely : H₂O

<h3>Further explanation  </h3>

Complete combustion of Hydrocarbons with Oxygen will be obtained by CO₂ and H₂O compounds.  

If O₂ is insufficient there will be incomplete combustion produced by CO and H and O  

Hydrocarbon combustion reactions (especially alkanes)  \large {\boxed {\bold {C_nH _ (_2_n _ + _ 2_) + \frac {3n + 1} {2} O_2 \Rightarrow nCO_2 + (n + 1) H_2O}}}

For combustion of propane C₃H₈ (n = 3) ⇒ completely(excess O₂) :

C₃H₈+5O₂⇒3CO₂+4H₂O

The products of combustion : CO₂ and H₂O

7 0
2 years ago
A gas effuses 1.55 times faster than propane (C3H8)at the
stepladder [879]

Answer:  The mass of the gas is 18.3 g/mol.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

\frac{Rate_{X}}{Rate_{C_3H_8}}=1.55

\frac{Rate_{X}}{Rate_{C_3H_8}}=\sqrt{\frac{M_{C_3H_8}}{M_{X}}}

1.55=\sqrt{\frac{44}{M_{X}}

Squaring both sides and solving for M_{X}

M_{X}=18.3g/mol

Hence, the molar mas of unknown gas is 18.3 g/mol.

5 0
3 years ago
Read 2 more answers
what grade is learning What amount of thermal energy (heat) in joules required to raise the temperature of 25 grams of water fro
blsea [12.9K]

Answer:

10425 J are required

Explanation:

assuming that the water is entirely at liquid state at the beginning , the amount required is

Q= m*c*(T final - T initial)

where

m= mass of water = 25 g

T final = final temperature of water = 100°C

T initial= initial temperature of water = 0°C

c= specific heat capacities of water = 1 cal /g°C= 4.186 J/g°C ( we assume that is constant during the entire temperature range)

Q= heat required

therefore

Q= m*c*(T final - T initial)= 25 g * 4.186 J/g°C * (100°C- 0°C) = 10425 J

thus 10425 J are required

7 0
3 years ago
What mass percent solution will result from dissolving 0.126 moles of AgNO3 in 475 g. of water
Kruka [31]

Answer:

The answer to your question is: 4.5 %

Explanation:

0.126 moles of AgNO3

mass percent = ?

mass of water = 475 g

Formula

               weight percent = weight of solute / weight of solution x 100

Weight of solute

 MW AgNO3 = 108 + 14 + (16 x 3)

                      = 108 + 14 + 48

                     = 170 g

                        170 g of AgNO3 -------------------  1 mol

                        x                         ---------------------  0.126 moles

                        x = (0.126 x 170) / 1  = 21.42 g of AgNO3

Weight percent = 21.42/475 x 100

                          = 4.5 %

7 0
3 years ago
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