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Jlenok [28]
3 years ago
9

How many moles of ca(oh)2 are in 25ml of 1.5 M solution?

Chemistry
1 answer:
Klio2033 [76]3 years ago
6 0
Molar concentration is

C=\frac{\eta}{V}

[V]=Liters

[\eta]=mol

\eta=C*V

V=25~mL=0.025~L

\eta=1.5*0.025

\boxed{\boxed{\eta=0.0375~moles}}
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What is the correct corresponding values of potassium
Tomtit [17]

Answer:

The reference ranges for blood potassium levels are as follows : Adult/elderly: 3.5-5.0 mEq/L or 3.5-5.0 mmol/L (SI units) Child: 3.4-4.7 mEq/L. Infant: 4.1-5.3 mEq/L.

Explanation:

6 0
3 years ago
The reaction below is at equilibrium. What would happen if more carbon were
schepotkina [342]

Explanation:

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When we would add more number of carbon in above reaction then rate of forward reaction will increase to attain the equilibrium again.

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5 0
2 years ago
A beaker contains 0.125 L of a 3.00 M solution. If the volume goes up to 0.325 L, what is the new molarity?
igor_vitrenko [27]

Answer:

1.15 M

Explanation:

Step 1: Given data

  • Initial volume (V₁): 0.125 L
  • Initial concentration (C₁): 3.00 M
  • Final volume (V₂): 0.325 L
  • Final concentration (C₂): ?

Step 2: Calculate the final concentration of the solution

We want to prepare a dilute solution from a concentrated one by adding water. We can calculate the concentration of the dilute solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂

C₂ = 3.00 M × 0.125 L/0.325 L = 1.15 M

8 0
2 years ago
10.0 mL of 3.0 M sulfuric acid has been added to 50.0 mL of water.
Cloud [144]

Answer:

the new concentration is 0.60M

Explanation:

The computation of the new concentration is shown below;

We know that

M1V1=M2V2

(3.0M) (10.0 mL) = M2 (50.0mL)

30 = M2 (50.0mL)

So, M2 = 0.60 M

Hence, the new concentration is 0.60M

The same is considered and relevant

3 0
3 years ago
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liq [111]

Answer:

1.D

2.A

3.C

4.A

Explanation:

6 0
3 years ago
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