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Stella [2.4K]
3 years ago
12

Please select the word from the list that best fits the definition

Chemistry
1 answer:
den301095 [7]3 years ago
8 0

Answer:

carboxylic acid

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What is the percent by mass of carbon in acetone c3h6o
Volgvan

Well, the molar mass of acetone would be

3(12.011)+6(1.008)+15.999 , which cleans up to be 58.08 grams.

out of this total, 3(12.011), or 36.033 grams are carbon

So, to find the percent, you do part over whole

36.033/58.08, which equals 0.6204 with significant figures

multiply that by 100 to get 62.04%

Hope that helps!

7 0
3 years ago
Read 2 more answers
What volume (cm​ 3​ ) would 9.0 grams of aluminum occupy? Density is 2.7 g/cm​ 3​ . Show your work
saul85 [17]

Answer:

3.3 cm³

Explanation:

Use the density formula, d = m/v, to solve for the volume:

2.7 = 9.0/v

2.7v = 9.0

v = 3.3 cm³

5 0
4 years ago
What is the equation for potassium chloride
Lina20 [59]
The equation for this is:
<span>KCl</span>
7 0
4 years ago
Read 2 more answers
How do we know what's inside an atom?
Lemur [1.5K]

Answer:

To really 'see' inside the atom and detect fundamental particles we need to go beyond visible light and bounce particles off the smallest building blocks of the Universe to 'observe' them. This session introduces students to the scientific process—how scientific methods and theories are updated and develop as new evidence and information is collected.

Explanation:

7 0
3 years ago
Calculate the equilibrium constant Kp for this reaction, given the following information (at 299 K ): 2NO(g)+Br2(g)⇌2NOBr(g)Kc=2
Travka [436]

Answer:

2NO_{(g)}+Br_2_{(g)}\rightleftharpoons2NOBr_{(g)} , Kp = 0.08967

2NO_{(g)}\rightleftharpoons N_2_{(g)}+O_2_{(g)} , Kp = 2.3×10³⁰

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

Where,

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

2NO_{(g)}+Br_2_{(g)}\rightleftharpoons2NOBr_{(g)}

Given: Kc = 2.2

Temperature = 299 K

R = 0.082057 L atm.mol⁻¹K⁻¹

Δn = (2)-(2+1) = -1

Thus, Kp is:

K_p= 2.2\times (0.082057\times 299)^{-1}

<u>Kp = 0.08967 </u>

For the second equilibrium reaction:

2NO_{(g)}\rightleftharpoons N_2_{(g)}+O_2_{(g)}

Given: Kc = 2.3×10³⁰

Temperature = 299 K

R = 0.082057 L atm.mol⁻¹K⁻¹

Δn = (2)-(2) = 0

Thus, Kp is:

K_p= 2.2\times (0.082057\times 299)^{0}

<u>Kp =  2.3×10³⁰</u>

3 0
3 years ago
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