I need help solving the question?????????

Mathematics

2 answers:

Helen [10]3 years ago

6 0

Answer:

x.......y

-8...-2

-1....1

0....0

1....-1

8...2

TEA [102]3 years ago

6 0

Answer:

-2

-1

Step-by-step explanation:

in order to find the y values you need to plug in the x values in the table into the function

the cube root of -8 is -2 (since this is a cube root instead of a square root we can have negative values in it because when we cube negative values we get negative values i.e. -2³=-8 ; -3³=-27)

the cube root of -1 is -1

the cube root of 0 is 0

the cube root of 1 is 1

the cube root of 8 is 2

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for any positive integer n, the sum of the first n positive integers equals n(n 1)/2. what is the sum of all the even integers b

marusya05 [52]

The sum of all the even integers between 99 and 301 is 20200

To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.

In this case, the first even integer will be 100 and the last even integer will be 300.

nth term of the AP = first term + (n-1) x common difference

⇒ 300 = 100 + (n-1) x 2

Therefore, n = (200 + 2 )/2 = 101

That is, there are 101 even integers between 99 and 301.

Sum of the 'n' terms in an AP = n/2 ( first term + last term)

= 101/2 (300+100)

= 20200

Thus sum of all the even integers between 99 and 301 = 20200

Learn more about arithmetic progressions at brainly.com/question/24592110

#SPJ4

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