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Juliette [100K]
2 years ago
10

The EPA sets national air-quality standards for common air pollutants. The

Chemistry
1 answer:
Troyanec [42]2 years ago
7 0

Answer:

A

Explanation:

Just took the quiz

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The number of neutrons and protons in the nuclei of two atom A and B is as follow: [A] proton= 8 and neutron = 8, [B] proton = 8
sveticcg [70]
A.atomic mass(a)=16
atomic mass(b)=18
b.a and b are isotopes
c.(a)=2,6
(b)=2,6
4 0
3 years ago
Which is true about metals used for jewelry, such as platinum and gold? A. They have low flammability. B. They have low reactivi
Morgarella [4.7K]

i think the answer is B. They have low reactivity.Hope this helped (:

8 0
3 years ago
Read 2 more answers
Which model can be used to trace genetic inheritance
Vesnalui [34]
To tract genetic inheritance ( phenotype or genotype) from one generation to another generation, PEDIGREE CHART is used. Pedigree Chart is a diagram shows the occurrence and appearance of a particular genes of an individual organism from its ancestor down to the generations it follows. Relationship in a pedigree is shown as a series of linear graph. Parents are connected to a horizontal lines while vertical lines will lead to the offspring.
5 0
3 years ago
In the laboratory a student uses a "coffee cup" calorimeter to determine the specific heat of a metal. She heats 19.6 grams of z
storchak [24]

Answer:

The specific heat of zinc is 0.375 J/g°C

Explanation:

<u>Step 1: </u>Data given

Mass of zinc = 19.6 grams

Mass of water = 82.9 grams

Initial temperature of zinc T1= 98.37 °C

Initial temperature of water T1= 24.16 °C

Final temperature of water (and zinc) T2 = 25.70 °C

Specific heat of water = 4.184 J/g°C

<u>Step 2: </u>Calculate Specific heat of zinc

Q=m*c*ΔT

Qzinc = -Qwater

m(zinc)*C(zinc)*ΔT(zinc) = -m(water)*C(water)*ΔT(water)

⇒ with mass of water = 82.9 grams

⇒ with C(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.70 - 24.16 = 1.54

⇒ with mass of zinc = 19.6 grams

⇒ with C(zinc) = TO BE DETERMINED

⇒ with ΔT(zinc) = T2 -T1 = 25.70 - 98.37 = -72.67°C

Qzinc = -Qwater

m(zinc)*c(zinc)* ΔT(zinc) = - m(water)*c(water)* ΔT(water)

19.6g* C(zinc) * (-72.67°C) = - 82.9g* 4.184 J/g°C * 1.54 °C

-1424.332*C(zinc) = -534.155

C(zinc) = 0.375 J/g°C

The specific heat of zinc is 0.375 J/g°C

4 0
3 years ago
Calculate the [H+]
ELEN [110]

[H⁺]=6.696 x 10⁻⁵

pH = 4.174

<h3> Further explanation </h3>

Given

The concentration of 0.000295 M (2.95 x 10⁻⁴ M) butanoic acid solution

Required

the [H+]  and pH

Solution

Butanoic acid is the carboxylic acid group. Carboxylic acids are weak acids

For weak acid :

\tt [H^+]=\sqrt{Ka.M}

Input the value :

[H⁺]=√1.52 x 10⁻⁵ x 2.95 x 10⁻⁴

[H⁺]=6.696 x 10⁻⁵

pH = - log [H⁺]

pH = - log 6.696 x 10⁻⁵

pH = 5 - log 6.696

pH = 4.174

5 0
3 years ago
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