Ask question

Ask question

All categories

2 years ago

10

Check the boxes next to events or trends that first occurred in science from about 1700. Darwin published his theory of natural

selection. Archimedes described the principle of the lever. Scientific societies and academies were formed. The double-helix structure of DNA was determined. Copernicus proposed a Sun-centered universe. Continental drift was explained by the theory of plate tectonics. The Earth was proven to be spherical.

2 answers:

pantera1 [17]2 years ago

8 0

Darwin published his theory of natural selection

Scientific societies and academies were formed.

The double-helix structure of DNA was determined.

Continental drift was explained by the theory of plate tectonics

got it right

marishachu [46]2 years ago

4 0

Check the boxes next to events or trends that first occurred in science from about 1700.

X Darwin published his theory of natural selection.

-Darwin published his work in 1859.

X Archimedes described the principle of the lever.

-Archimedes discovered this during the third century BC (300-201 BC)

/ Scientific societies and academies were formed.

-These were formed around 1789

X The double-helix structure of DNA was determined.

<span> -IT was discovered in 1953 by James Watson and Francis Crick.</span>

X Copernicus proposed a Sun-centered universe.

<span>-It was proposed in the 16th century.</span>

X Continental drift was explained by the theory of plate tectonics.

<span> -It was proposed at around 1910 till 1950 but was accepted at 1960. </span>

X The Earth was proven to be spherical.

-It was argued at around 384-322 BC.

You might be interested in

How many protons are there in H2S ?

Vinvika [58]

16. Hope this helps!!

3 0

3 years ago

What is the identity of the element which had the following electron configuration? 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5

kati45 [8]

Answer:

The element with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5 is manganese (25Mn).

Explanation:

Step 1: Data given

The element with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5

has 25 electrons.

This element has 2 electrons on the first shell, 8 electrons on the second shell, 13 electrons on the third shell and 2 electrons on the outer shell (valence electrons).

This means this element is part of group VII.

The element with 25 electrons, we can find on the periodic table, with atomic number 25.

The element with electron configuration 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^5 is manganese (25Mn).

5 0

3 years ago

A. Energy is transferred to different forms

Luden [163]

Answer:

A. Energy is transferred to different forms .

Explanation:

Hello!

In this case, we need to consider the law of conservation of mass and energy which states that mass and energy cannot be neither created nor destroyed, just modified; it means we can rule out B. and C. so far.

Moreover, since D. is actually true for combustion reactions because they are used to provide energy in industrial operations, this is not the concern here because a combustion reaction is not considered.

Therefore the correct option is A. Energy is transferred to different forms as the energy provided by Rose is transferred to the pendulum system .

Best regards!

3 0

3 years ago

The solubility of oxygen in lakes high in the Rocky Mountains is affected by the altitude. If the solubility of O2 from the air

IceJOKER [234]

Answer:

$1.75\cdot 10^{-4} M$

Explanation:

Henry's law states that the solubility of a gas is directly proportional to its partial pressure. The equation may be written as:

$S = k_H p^o$

Where $k_H$ is Henry's law constant.

Our strategy will be to identify the Henry's law constant for oxygen given the initial conditions and then use it to find the solubility at different conditions.

Given initially:

$S_1 = 2.67\cdot 10^{-4} M$

Also, at sea level, we have an atmospheric pressure of:

$p = 1.00 atm$

Given mole fraction:

$\chi_{O_2} = 0.209$

According to Dalton's law of partial pressures, the partial pressure of oxygen is equal to the product of its mole fraction and the total pressure:

$p^o = \chi_{O_2} p$

Then the equation becomes:

$S_1 = k_H \chi_{O_2} p$

Solve for $k_H$ :

$k_H = \frac{S_1}{\chi_{O_2} p} = \frac{2.67\cdot 10^{-4} M}{0.209\cdot 1.00 atm} = 0.001278 M/atm$

Now we're given that at an altitude of 12,000 ft, the atmospheric pressure is now:

$p = 0.657 atm$

Apply Henry's law using the constant we found:

$S_2 = k_H \chi_{O_2} p = 0.001278 M/atm\cdot 0.209\cdot 0.657 atm = 1.75\cdot 10^{-4} M$

8 0

3 years ago

What is the metric unit for mass?<br> a.Meters<br> b.Kilograms<br> c.Pounds<br> d.matter

fiasKO [112]

The metric unit for mass is B. Kilograms

7 0

3 years ago