In a water molecule, the oxygen atom and hydrogen atoms share electrons in covalent bonds, but the sharing is not equal. In the covalent bond between oxygen and hydrogen, the oxygen atom attracts electrons a bit more strongly than the hydrogen atoms.
Volume of room = 
= 
Now, according to conversion factor, convert 6,400 mg to micrograms
Since, 1 mg is equal to 1000 microgram.
Therefore, 6,400 mg = 
= 6,400,000 micrograms of acetone.
To calculate concentration of acetone, divide volume and evaporated amount of acetone in micrograms.
Thus,
Concentration of acetone = 
= 39296.5910 microgram per cubic meter or 
Hence, concentration of acetone is equal to 
KE=6,250Joules
You plug in your given numbers and remember to square 5 because that’s the speed
3-B
4-C
5-A
6-A
7-C
8-B
9-A
10-B
Answer:
The answer to your question is below
Explanation:
Propane = C₃H₈
Process
1.- Write the chemical reaction
C₃H₈ + O₂ ⇒ CO₂ + H₂O
balanced chemical reaction
C₃H₈ + 5O₂ ⇒ 3CO₂ + 4H₂O
Reactants Elements Products
3 C 3
8 H 8
10 O 10
b) Standard enthalpy
Propane -104.7 kJ/mol
Oxygen 0 kJ/mol
Carbon dioxide -393.5 kJ/mol
Water -241.8 kJ/mol
ΔH° = ∑ΔH° products - ∑H° reactants
ΔH° = 3(-393.5) + 4(-241.8) - [(-104.7) + 0]
-Simplification
ΔH° = -1180.5 kJ/mol - 967.2 kJ/mol + 104.7 kJ/mol
ΔH° = - 2042.5 kJ/mol
This reaction is exothermic because ΔH° is negative.
