First we will convert those radian angles to degrees, since my mind works better with degrees. Let's work one at a time. First, 
. If we start at the positive x-axis and measure out 315 we end up in the 4th quadrant with a reference angle of 45 with the positive x-axis. The side across from the reference angle is -1, the side adjacent to the angle is 1, and the hypotenuse is sqrt2. The cotangent of this angle, then is 1/-1 which is -1. As for the second one, converting radians to degrees gives us that 
. Sweeping out that angle has us going around the origin more than once and ending up in the first quadrant with a reference angle of 30° with the positive x-axis. The side across from the angle is 1, the side adjacent to the angle is √3, and the hypotenuse is 2. Therefore, the secant of that angle is 2/√3.
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Answer:
The domain of function is set of all real numbers.
Domain: (-∞,∞)
Step-by-step explanation:
Given:
the domain of both the above functions is all real number.
To find domain of :
Substituting functions and
to find
The product can be written as difference of squares.
∴
The degree of the function is 2 as the exponent of leading term
is 2. Thus its a quadratic equation.
For any quadratic equation the domain is set of all real numbers.
So Domain of is (-∞,∞)