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3 years ago

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A ball rolls over the edge of a platform with only a horizontal velocity. The height of the platform is 1.6 m and the horizontal

range of the ball from the base of the platform is 20 m. What is the horizontal velocity of the ball just before it touches the ground?

1 answer:

Sever21 [200]3 years ago

3 0

Explanation:

the answer is in the above image

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Find out the speed of the car from home to school in meters per second.

julia-pushkina [17]

1.875

Explanation:

speed = distance moved ÷ time taken

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3 years ago

An output is a Push or pull _________________________ on the object

Ugo [173]

Answer:

The input force that you use on an inclined plane is the force with which you push or pull an object. The output force is the force that you would need to lift the object without the inclined plane. This force is equal to the weight of the object.

Explanation:

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4 years ago

How does fabric softener help prevent static electricity?

algol13

Answer:

Dryer sheets stop static cling by absorbing static electricity formed by different fabrics during your dryer cycle. The fabric softeners that coat dryer sheets are positively charged ions to balance the electrons and ions that cause static cling, leaving you with soft clothes without the static.

Explanation:

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2 years ago

A dielectric-filled parallel-plate capacitor has plate area A = 30.0 cm2 , plate separation d = 9.00 mm and dielectric constant

PIT_PIT [208]

Answer:

$9.96\cdot 10^{-10}J$

Explanation:

The capacitance of the parallel-plate capacitor is given by

$C=\epsilon_0 k \frac{A}{d}$

where

ϵ0 = 8.85x10-12 C2/N.m2 is the vacuum permittivity

k = 3.00 is the dielectric constant

$A=30.0 cm^2 = 30.0\cdot 10^{-4}m^2$ is the area of the plates

d = 9.00 mm = 0.009 m is the separation between the plates

Substituting,

$C=(8.85\cdot 10^{-12}F/m)(3.00 ) \frac{30.0\cdot 10^{-4} m^2}{0.009 m}=8.85\cdot 10^{-12} F$

Now we can calculate the energy of the capacitor, given by:

$U=\frac{1}{2}CV^2$

where

C is the capacitance

V = 15.0 V is the potential difference

Substituting,

$U=\frac{1}{2}(8.85\cdot 10^{-12}F)(15.0 V)^2=9.96\cdot 10^{-10}J$

4 0

3 years ago

A 240-volt, 2-amp motor is connected to a three-wire, 120/240-volt system. Connected between the black wire and neutral are four

pantera1 [17]

Answer:

(i)The current flow in black wire = 9.67 A (ii) The current low in the red wire is 9.68 A (iii) The current flow in neutral wire is 15.36 A (iv) when 240 volt were disconnected current in black wire is 7.68 A (v) when 240 volt were disconnected current in red wire is 7.68 A (vi) 15.36 A (vii) 6.34 (viii) 9.68 A (ix) 12.02 A

Explanation:

Solution

The current drawn by one amp is

I =P/V

I =200/120

I= 1.67 A

(i) The current flow in the black wire is

IBK = 4 * 1.67 A + 1A + 2A

IBK = 9.67 A

(ii) Current flow in the red wire is

IRD = 3 * 1.67 A + 1.67 A + 1A + 2A

= 8.68A + 1 A = 9.68 A

Note: Kindly find an attached copy of part of the solution to the given question above.

6 0

4 years ago