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bearhunter [10]
3 years ago
9

How do I calculate the total volume for the objects below using V=l×w×h​

Mathematics
2 answers:
MAVERICK [17]3 years ago
7 0

Answer:

4m*3m*3m - 2m*2m*2m

Step-by-step explanation:

Fudgin [204]3 years ago
6 0

Answer:

V=12m

Step-by-step explanation:

V=l×w×h​

V=3×4×1

V=12m

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Answer:

0.33

Step-by-step explanation:

0.53

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3 0
3 years ago
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D = 8 cm<br> h = 18 cm<br> What is the surface area of the cylinder
mars1129 [50]

Answer:

144 (If multiplying)

Step-by-step explanation:

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5 0
3 years ago
If ADEF is reflected over the x-axis, what would be the coordinates of point F?
Brut [27]

Answer:

Please check the explanation.

Step-by-step explanation:

Let the coordinates of the point F be (x, y).

When a point F(x, y) is reflected over the x-axis, the x-coordinate of the point F remains the same, and the y-coordinate of the point reverses the sign.

Thus, the rule of reflection over the x-axis:

F(x, y)   →    F'(x, -y)

Here,

F'(x, -y) would be coordinates of point F after the reflection over the x-axis.

Let say, the point F(1, 2).

The coordinate of the point F after the reflection over the x-axis would be:

F(1, 2)   →    F'(1, -2)

Thus, F'(1, -2) would be the coordinates of point F after the reflection over the x-axis.

6 0
3 years ago
41 - 17= <br> i know it's 28 but i can't really do math
VikaD [51]
It’s 24 you can use a calculator
4 0
2 years ago
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Here is a triangular pyramid and its net.
bazaltina [42]

Answer:

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. \text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\

{\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>

\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\  mm^{2}

Hence,

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

3 0
3 years ago
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