<span>1. What causes water's low vapor pressure? (1 point)
dispersion forces
dispersion forces
covalent bonding
hydrogen bonding
ionic attractions
2. Which of the following substances is the most soluble in water? (1 point)
sodium chloride
methane
bromine
carbon
3. Which of the following substances is NOT an electrolyte? (1 point)
KCl
CCl4
LiCl
Na2SO4
4. Which of the following mixture types can be filtered to remove solute? (1 point)
suspensions only
colloids only
suspensions and colloids
suspensions and solutions
5. Which of the following mixtures is NOT a colloid? (1 point)
fog
milk
paint
sugar water
6. Which of the following types of mixtures exhibit the Tyndall effect? (1 point)
suspensions and colloids
suspensions and solutions
colloids and solutions
colloids only
7. An emulsyfying agent is typically characterized by having ____. (1 point)
one polar end
one nonpolar end
one nonpolar end
two polar ends
one polar end and one nonpolar end</span>
First, we determine the energy required to melt one gram of ice. This is given by:
Energy = mass * latent heat of fusion
Energy = 1 g * 334 J/g
Energy = 334 J
Next, we use Planck's equation which is:
Energy = number of photons * Planck's constant * speed of light / wavelength
334 = n * 6.64 x 10⁻³⁴ * 3 x 10⁸ / 5.49 x 10⁻⁶
n = 9.20 x 10²¹
9.20 x 10²¹ photons need to be absorbed by the ice.
From rocks and lava and earthquakes
Na5Cl2
penta is 5, so 5 sodiums and di is 2, so 2 chloride
Wavelength is 6.976 x 10^ -35 m
Explanation:
In this, we can use De Broglie’s equation. This equation is the relationship between De Broglie’s wavelength, velocity and the mass of a moving object. In this equation, we are using plank's constant which is 6.626 x 10^-34 m^2 kg/s.
We know that one mile per hour is equivalent to 0.447 M/S.
And One gram is equivalent to 10^-3 kg.
De Broglie’s wavelength = λ ( wave length) = Plank’s constant/ Mass x velocity
λ ( wave length) = 6.626 x 10^ -34/ (425 x10^-3) x ( 50 x 0.447)
= 6.626 x 10^ -34/ 0. 425 x 22.35
= 6.626 x 10^ -34/ 9.498
= 6.976 x10^ -35 m
So, the wavelength of the football will be 6.976 x 10^ -35 m
