The intercepts for x+y=5
X= (5,0)
Y= (0,5)
Slope is 3 and y intercept is (0,7)
The pythagorean theorem is only used for right triangles? however, you can find the equation with the info given. a circle is written as (x-h)^2+(y-k)^2=r^2. in this scenario, h=-2, k=5, and r=4.
Your final equation would be (x+2)^2+(y-5)^2=16
The perimeter = 20 and AC = 8
Now as it is not mentioned which sides are equal of the isosceles triangle ABC,
We have two possible situations.
1)
If AC is the base
In that case AB = BC
Now AC = 8, AB = x , BC = x
So x + x + 8 = 20
2x + 8 = 20
2x = 12
x = 6
AB = BC = 6
2)
IF AC is not the base,
Then
AC = BC or AC = AB
So BC = 8 or AB = 8
If AB = AC = 8
Then
BC + 8 + 8 = 20
BC = 4
So there are two possible lengths of BC
Either it is BC = 8 or BC = 6 or BC = 4
The figure is attached for your reference.
I believe that f(2) is 34.5
f(2) = 2(34) + 1
f(2) = 68 + 1
f(2) = 69
f = 69/2
f = 34.5
I AM NOT SURE
Answer:
the question answer is A
Step-by-step explanation: